Ask Your Question

Incorrect result for complex integral

asked 2022-02-28 01:04:21 +0200

ripple_carry gravatar image

Not sure if this is user error: I am trying to evaluate the following integral:

f = sqrt((e^(i * t) - 1) * (e^(-i*t) - 1))
show(f.integrate(t, 0, 2 * pi))

Sagemath returns 0, but WolframAlpha returns 8. Have I mis-specified the problem, or is this a bug?

edit retag flag offensive close merge delete


mwageringel gravatar imagemwageringel ( 2022-02-28 08:29:39 +0200 )edit

2 Answers

Sort by ยป oldest newest most voted

answered 2022-02-28 23:13:55 +0200

Emmanuel Charpentier gravatar image

updated 2022-02-28 23:14:21 +0200

A slight complement to Nasser's answer :

Contemplate :

sage: graphics_array(([f(t).demoivre(force=True).simplify_full().integrate(t, algorithm=u).plot((0,2*pi), title=u) for u in ("maxima", "giac", "fricas", "mathematica_free")]),ncols=2)

image description

(sympy fails to integrate the expression).

maxima problems with various trig integrals have been documented for a long time... giac, fricas and mathematica give different expressions of similar functions (up to a constant), but proving the identities isn't trivlal (long algebrico/trigonometric massage ahead...).

But note :

sage: table([[u, f(t).demoivre(force=True).simplify_full().integrate(t, algorithm=u)] for u in ("maxima", "giac", "fricas", "mathematica_free")], header_row=["Algorithm", "Antiderivative"])
  Algorithm          Antiderivative
  maxima             -4/sqrt(sin(t)^2/(cos(t) + 1)^2 + 1)
  giac               -4*cos(1/2*t)*sgn(sin(1/2*t)) + 4*sgn(sin(1/2*t))
  fricas             -2*(cos(t) + 1)*sqrt(-2*cos(t) + 2)/sin(t)
  mathematica_free   -2*sqrt(-2*cos(t) + 2)*cot(1/2*t)

ALL those "CAS primitives" are periodic of period $2\pi$, whereas the function $\displaystyle\int_0^t f(t)\,dt$ is not ($f$ is positive except for a null-measure set ($t=2k\pi,\ k\in\mathbb{Z}$) where it is zero, therefore its integral is increasing). Computing the integral by taking limits of the primitive at bounds is wrong.

This happens to be plotted in the above figure for the fricas and mathematica cases. This (and the fact that it is not plotted for giac) is pure numerical happenstance...

Morality : never trust a CAS result without checking it...


edit flag offensive delete link more

answered 2022-02-28 04:21:33 +0200

Nasser gravatar image

updated 2022-02-28 04:55:59 +0200

Mathematica is correct. You can see that easily by plotting the integrand from 0 to 2Pi. Clearly the area is not zero. It looks like about 8 is correct.

Here is a workaround in sagemath,

Write the integrand using trig function by converting it using Euler's formula. This will give sqrt(2-2*cos(t)) and now integrate this instead of the complex exponential. But make sure to use "fricas" as algorithm. The default algorithm and others give zero which is wrong.

f = sqrt((e^(I * t) - 1) * (e^(-I*t) - 1))
g = expand(sageobj(f._maxima_().demoivre())).trig_simplify()

     sqrt(-2*cos(t) + 2)

Now integrate the above, but use "fricas" to get correct answer

sage: integrate(g, t, 0, 2 * pi, algorithm="fricas")


Compare to

sage: integrate(g, t, 0, 2 * pi)
edit flag offensive delete link more

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

1 follower


Asked: 2022-02-28 01:04:21 +0200

Seen: 569 times

Last updated: Feb 28 '22