Hi there, total beginner in Sage, and this drives me mad:
def mylimit(f,x,a):
return f.limit(x=a)
var('y')
mylimit(1/y,y,2).show()which always returns: 1/y...
How shall I specify that x should be a var?
Thanks in advance.
Defining a variable inside the function, we can use it for the limit.
For example, define t and substitute it for the variable provided by the user.
Applying this idea, we can define myfunction as follows:
def mylimit(f, x, a):
r"""
Return the limit of the expression `f` when `x` tends to `a`.
"""
t = SR.var('t')
return f.subs({x: t}).limit(t=a)With that definition:
sage: mylimit(1/y, y, 2)
1/2Thank you!
You are welcome. If it solves the question, you can mark the answer as accepted by clicking the "accept" button next to it (the button with a check mark). This also marks the question as solved in the list of questions.
Asked: 3 years ago
Seen: 376 times
Last updated: Mar 28 '22
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