jafrancor's profile - activity

I don't understand what implies and what is the meaning of checking that the result of..dimension() is indeed 0 before a

Thank you too!!

Thanks a lot!!

For example:

var('a,b,c,d,e,f,g,h,i,j,k,l,x,y,p,q,r,s,t,u,v,A,B,C,D,E,F,G,H,T,K,L,M,N')
solve([A - E, A*E - B, B*E - C, C*E - D - 10, D*E + 2], A,B,C,D,E, solution_dict=true)

[{A: 1.724306472919419,
  B: 2.973232669869595,
  C: 5.126764621146644,
  D: -1.159886628876292,
  E: 1.724306472919419},
 {A: -0.04961250951920438 - 1.781741795058672*I,
  B: -3.172142423158106 + 0.1767933635362254*I,
  C: 0.4723780710666982 + 5.643167572788117*I,
  D: 0.03123165940893102 - 1.121627457212148*I,
  E: -0.04961250951919667 - 1.781741795058679*I},
 {A: -0.04961250951920438 + 1.781741795058672*I,
  B: -3.172142423158106 - 0.1767933635362254*I,
  C: 0.4723780710666982 - 5.643167572788117*I,
  D: 0.03123165940893102 + 1.121627457212148*I,
  E: -0.04961250951919667 + 1.781741795058679*I},
 {A: -1.825113562621674,
  B: 3.331039229181005,
  C: -6.079524680073126,
  D: 1.095822281167109,
  E: -1.825113562621674},
 {A: 0.2000320307495195,
  B: 0.04001281142046625,
  C: 0.008003843719970937,
  D: -9.99839871897518,
  E: 0.2000320307495195}]

But I only need to print the list of the C solutions. Say:

[ C: 5.126764621146644,
  C: 0.4723780710666982 + 5.643167572788117*I,
  C: 0.4723780710666982 - 5.643167572788117*I,
  C: -6.079524680073126,
  C: 0.008003843719970937]

Or something like that.

In the example

var('f, q, r, h, i, g, x, y, z')
eq1 = x^5 - x^4 - 2*x^3 + 2*x^2 + x - 1
solve(eq1==0,x)

Where, this equation is also equal to (x-1)^3*(x+1)^2, but I obtain the following solution:

[x == -1, x == 1]

Let's say that, in any equation, repeated solutions are given by Sage only once.

Then, how can I, in our example, obtain the following complete solution?

[x == -1, x == -1, x == 1, x == 1, x == 1]

In a system of 5 nonlinear equations with 5 unknowns using the solve command, Sage gives 5 lists of 5 solutions. Is it p

Thanks a lot!

Why, in any equation, are repeated solutions given by Sage only once? In the example var('f, q, r, h, i, g, x, y, z') e

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I didn't have any result

Fortunately, by using a concrete example I achieved for q=2 and r=1 the solution of "solve([e1, e2, e3, e4], [f, g, h,

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I didn't have any result

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I didn't have any result

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I didn't have any result

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I didn't have any result

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I didn't have any result

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I didn't have any result

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I don't have any result f

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I don't have any result f

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I don't have any result f

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I don't have any result f

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I don't have any result f

Fortunately, by using a concrete example I achieved for q=2 and r=1 the solution of "solve([e1, e2, e3, e4], [f, g, h,

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I don't have any result f

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I don't have any result f

Of course I tried with "solve([e1, e2, e3, e4. e5], [f, g, h, i, d], solution_dict=True)", but I don't have any result f

Fortunately, by using concrete examples I achieved, for q=2 and r=1, the complete solution of "solve([e1, e2, e3, e4], [

Fortunately by using concrete examples I achieved, for q=2 and r=1, the complete solution of "solve([e1, e2, e3, e4], [f

Fortunately by using concrete examples I achieved, for q=2 and r=1, the complete solution of "solve([e1, e2, e3, e4], [f

Fortunately by using concrete examples I achieved, for q=2 and r=1, the complete solution of "solve([e1, e2, e3, e4], [f

Fortunately by using concrete examples I achieved, for q=2 and r=1, the complete solution of "solve([e1, e2, e3, e4], [f

Fortunately by using concrete examples I achieved, for q=2 and r=1, the complete solution of "solve([e1, e2, e3, e4], [f