jack77's profile - activity

@Christ what is about

RememberInteger=Integer ... Integer=int ... Integer= RememberInteger

@tmonteil is it also possible to get the branch test coverage for Sage?

What do you think, is the number misleading? Sage uses external libraries, but their test code coverage is not recognized, if available at all.

For a particular file:

sage --coverage <filename>

For all Sage library:

sage --coverageall

For Sage 6.2, the overall weighted coverage score is 93.7%.

The doc is available here.

How can a user get/see recent Sage doctest coverage statistics?

Thanks,

Jack

Hello,

I do not know, if this construction is useful, but you could do the following:

 import numpy as np


 L1 = np.array( [1,2] )                         
 L2 = np.array( [1,2,3] )
 L3 = np.array( [3,2,2,3] )

 L = np.array( [L1, L2, L3], dtype=object )

 L[0] # will return array([1, 2])

if the number of the basic arrays are not known or is variable,
you could compose a command string and then use

count = 3
cmdstr = "L = np.array(["
for i in range(1, count):   cmdstr = cmdstr+ 'L'+str(i)+','
cmdstr = cmdstr+ 'L'+str(count)
cmdstr = cmdstr+"], dtype=object)"
cmdstr # : 'L = np.array([L1,L2,L3], dtype=object)'

exec(cmdstr) # L will be = array([[1 2], [1 2 3], [3 2 2 3]], dtype=object)

Remark: it did'nt work neither with np.concatenate nor with np.append

Hello,

I fear, creating finite multiplicative groups over Zp is not possible yet.

You could create an isomorphic one , e.g. for p = 7:

AbelianGroup([7])

but that is probably not what you want...

but it should!

I'm sorry, but this design is a failure - to return False when the result is Unknown. This should definitely be fixed.

Hello,

when assigning N to K, no data is copied, so you working on the original data, To keep the original, you need a deep copy of N:

 K=N.copy()

what did you tried so far to fill the POPOPO array?

@eviatar-bach returning False in case can't be determined whether a relation holds seems to me unwise ; This should be changed to a tristate-answer, whatever the third state is

Hello mresimulator, what type of arrays are the L1, L2,.. are they one-dimensional? btw, did you solve the problem already?

is this homework?

why did you not accept the answer from John?

Hello,

you should fix the code as suggested by John, and use

Arrangements(vals,2).list()

instead of

arrangements(vals,2)

but just for completeness, you can force Python to shut up with adding

import warnings
warnings.filterwarnings("ignore", category=DeprecationWarning)

Hello mresimulator,

I do not know, why you want to encode the index j in the name,
but you could use 'exec()' for this:

import numpy as np
N = 4
A = 3
for j in srange(N):
   exec('L'+str(j)+"=np.empty(A)")

Then L1 to L4 gets defined:

>>> L1
array([  9.79748720e-251,   2.90930926e-252,   2.34745402e-251])

'You can do it with just the groups' - you mean using summand_projection? 'of course that's not what you want' - yes, I would like something more comfortable

Well, the question is, is there a way to construct the product ring Z/nZ x Z/mZ in sage

Hello,

is it possible in Sage to construct a product ring of two integer modulo rings?

When just creating an cartesian_product, it is for example not possible to add its elements:

R5=Integers(5)
R3=Integers(3)
CR=R5.cartesian_product(R3)
elem=CR((3,2)) # ok, element construction
elem*elem # ok
elem+elem # fails 
CR.list() #  not implemented
CR.list_of_elements_of_multiplicative_group # not implemented

Hello, I'm not sure if I have an account for the sagemath tracker. Did you open an issue ticket for return value of 'list_of_elements_of_multiplicative_group' ?