Is it possible to get a multiplicative group object of integers modulo n?
For example for n=15 the elements are {1,2,4,7,8,11,13,14}
Of course I can get the elements itself with
R = Integers(15)
R.list_of_elements_of_multiplicative_group()
but not as a group.
It is also possible to construct the isomorphic group C2 x C4, but then the elements are not integers:
G=AbelianGroup([2,4])
The list_of_elements_of_multiplicative_group should definitely return elements of R, not Python integers. Somewhat ugly, but ok there is your group:
sage: M = map(R, R.list_of_elements_of_multiplicative_group())
sage: M[2]*M[5] in M
True
sage: prod(M) == 1
True
Now the isomorphism with C2 x C4 is not unique, so its not clear how this can be improved. Maybe one could return a particular morphism from C2 x C4 to R. In any case, as far as I know this is not (yet) implemented.
Asked: 2013-07-11 17:15:52 +0200
Seen: 1,270 times
Last updated: Jul 11 '13
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