### Help solving log equation for x

~~Hi, ~~I am trying to solve the following equation for ~~x, 1+2~~*log(x+1, 4)==2*log(x,2)`x`

:

```
1 + 2 * log(x + 1, 4) == 2 * log(x, 2)
```

I entered in the input ~~"(1+2~~*log(x+1, 4)==2*log(x,2)).solve(x,algorithm='sympy', domain='all')"

```
(1 + 2 * log(x + 1, 4) == 2 * log(x, 2)).solve(x, algorithm='sympy', domain='all')
```

and the ~~Output ~~output was ~~"{๐ฅโฃ๐ฅโโโงโ๐ฅ2log(2)+๐(๐ฅ+1)1log(2)=0}โ{๐ฅโฃ๐ฅโโโง๐ฅ2log(2)=0}"~~

{๐ฅโฃ๐ฅโโโงโ๐ฅ2log(2)+๐(๐ฅ+1)1log(2)=0}โ{๐ฅโฃ๐ฅโโโง๐ฅ2log(2)=0}

The answer I am looking for ~~is "x ~~is

`x = `~~1+3^(1/2)."~~1+3^(1/2)