# Help solving log equation for x

I am trying to solve the following equation for `x`

:

```
1 + 2 * log(x + 1, 4) == 2 * log(x, 2)
```

I entered in the input

```
(1 + 2 * log(x + 1, 4) == 2 * log(x, 2)).solve(x, algorithm='sympy', domain='all')
```

and the output was

{๐ฅโฃ๐ฅโโโงโ๐ฅ2log(2)+๐(๐ฅ+1)1log(2)=0}โ{๐ฅโฃ๐ฅโโโง๐ฅ2log(2)=0}

The answer I am looking for is

```
x = 1+3^(1/2)
```

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