# Revision history [back]

### Get point coordinates of curve over number field

Suppose I have equation of curve C:

curve
# => y^2 + (x^2 + x)*y + x
curve.parent()
# => Univariate Polynomial Ring in y over Rational function field in x over Rational Field


and I know that x that is root of another equation:

equation
# => x^3 + x^2 - 2*x - 9/2
equation.parent()
# => Univariate Polynomial Ring in x over Rational Field


is x-coordinate of some point of C.

How to properly get y-coordinate of C in x?

It is not as easy as it seems because of conversion problems.

My workaround is as following:

FF.<z> = NumberField(equation)
P.<x,y> = QQ[]

u = P(curve).subs(x=z)

P.<y> = FF[]
return z, P(u).roots()[0][0]


and it doesn't seem right.

Are there more elegant way of doing it?

### Get point coordinates of curve over number field

Suppose I have equation of curve C:

curve
# => y^2 + (x^2 + x)*y + x
curve.parent()
# => Univariate Polynomial Ring in y over Rational function field in x over Rational Field


and I know that there is a point with x that is value is a root of another equation: equation (i.e. element of corresponding Number Field):

equation
# => x^3 + x^2 - 2*x - 9/2
equation.parent()
# => Univariate Polynomial Ring in x over Rational Field


is x-coordinate of some point of C.

How to properly get y-coordinate of C in x?

It is not as easy as it seems because of conversion problems.

My workaround is as following:

FF.<z> = NumberField(equation)
P.<x,y> = QQ[]

u = P(curve).subs(x=z)

P.<y> = FF[]
return z, P(u).roots()[0][0]


and it doesn't seem right.

Are there more elegant way of doing it?

### Get point coordinates of curve over number field

Suppose I have equation of curve C:

curve
# => y^2 + (x^2 + x)*y + x
curve.parent()
# => Univariate Polynomial Ring in y over Rational function field in x over Rational Field


and I know that there is a point with x value is a root of another equation (i.e. element of corresponding Number Field):

equation
# => x^3 + x^2 - 2*x - 9/2
equation.parent()
# => Univariate Polynomial Ring in x over Rational Field


is x-coordinate of some point of C.

How to properly get y-coordinate of C in x?

It is not as easy as it seems because of conversion problems.

My workaround is as following:

FF.<z> = NumberField(equation)
P.<x,y> = QQ[]

u = P(curve).subs(x=z)

P.<y> = FF[]
return z, P(u).roots()[0][0]


and it doesn't seem right.

Are there more elegant way of doing it?

P.S. curve is constructed as follows:

 F = FunctionField(QQ, 'x') x = F.gen() R.<y> = F[]

  curve = y^2 + (x^2 + x)*y + x;




But it was done in another place so I have no direct access to x and y from above code.

### Get point coordinates of curve over number field

Suppose I have equation of curve C:

curve
# => y^2 + (x^2 + x)*y + x
curve.parent()
# => Univariate Polynomial Ring in y over Rational function field in x over Rational Field


and I know that there is a point with x value is a root of another equation (i.e. element of corresponding Number Field):

equation
# => x^3 + x^2 - 2*x - 9/2
equation.parent()
# => Univariate Polynomial Ring in x over Rational Field


is x-coordinate of some point of C.

How to properly get y-coordinate of C in x?

It is not as easy as it seems because of conversion problems.

My workaround is as following:

FF.<z> = NumberField(equation)
P.<x,y> = QQ[]

u = P(curve).subs(x=z)

P.<y> = FF[]
return z, P(u).roots()[0][0]


and it doesn't seem right.

Are there more elegant way of doing it?

P.S. curve is constructed as follows:



  F = FunctionField(QQ, 'x')
x = F.gen()
R.<y> = F[] F[]

curve = y^2 + (x^2 + x)*y + x;
 But it was done in another place so I have no direct access to x and y from above code. 





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