Get point coordinates of curve over number field

asked 2020-06-01 07:56:20 -0500

petRUShka gravatar image

updated 2020-06-01 15:49:39 -0500

Suppose I have equation of curve C:

curve 
# => y^2 + (x^2 + x)*y + x
curve.parent()
# => Univariate Polynomial Ring in y over Rational function field in x over Rational Field

and I know that there is a point with x value is a root of another equation (i.e. element of corresponding Number Field):

equation
# => x^3 + x^2 - 2*x - 9/2
equation.parent()
# => Univariate Polynomial Ring in x over Rational Field

is x-coordinate of some point of C.

How to properly get y-coordinate of C in x?

It is not as easy as it seems because of conversion problems.

My workaround is as following:

FF.<z> = NumberField(equation)
P.<x,y> = QQ[]

u = P(curve).subs(x=z)

P.<y> = FF[]
return z, P(u).roots()[0][0]

and it doesn't seem right.

Are there more elegant way of doing it?

P.S. curve is constructed as follows:

  F = FunctionField(QQ, 'x')
  x = F.gen()
  R.<y> = F[]

  curve = y^2 + (x^2 + x)*y + x;

But it was done in another place so I have no direct access to x and y from above code.

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Comments

Could you please provide the construction of curve ?

tmonteil gravatar imagetmonteil ( 2020-06-01 08:46:03 -0500 )edit

@tmonteil, I've added P.S. with details

petRUShka gravatar imagepetRUShka ( 2020-06-01 15:49:28 -0500 )edit