Polynomial equations in binary finite fields are often represented as numbers. eg. $x^2 + 1$ is basically the same thing as $1x^2 + 0x^1 + 1x^0$ and thus would be represented as $101_2$ or $5_{10}$.

In that spirit I'm trying to use a hexadecimal number to represent a polynomial equation. The polynomial equation is larger than the modulo I'm using ($x^{113} + x^9 + 1$) so I'm trying to get the result of the modulo operation.

Here's what I've tried:

```
BF.<a> = FiniteField(2^113);
X = Integer(0x61661990d3b1f7a608ad095a01d727380850d2592f5b9f88f66a20e8);
X_bf = BF._cache.fetch_int(X);
X_bf.mod(x^113 + x^9 + 1)
```

Unfortunately, this doesn't seem to work and instead gets me the following error messages:

```
TypeError Traceback (most recent call last)
<ipython-input-4-dba4addbde0d> in <module>()
2
3 X = Integer(Integer(0x61661990d3b1f7a608ad095a01d727380850d2592f5b9f88f66a20e8));
----> 4 X_bf = BF._cache.fetch_int(X);
5
6 X_bf.mod(x**Integer(113) + x**Integer(9) + Integer(1))
/home/sage/sage-8.0/src/sage/rings/finite_rings/element_ntl_gf2e.pyx in sage.rings.finite_rings.element_ntl_gf2e.Cache_ntl_gf2e.fetch_int (/home/sage/sage/src/build/cythonized/sage/rings/finite_rings/element_ntl_gf2e.cpp:7596)()
400 raise ValueError("Cannot coerce element %s to this field." % e)
401
--> 402 cpdef FiniteField_ntl_gf2eElement fetch_int(self, number):
403 """
404 Given an integer less than `p^n` with base `2`
/home/sage/sage-8.0/src/sage/rings/finite_rings/element_ntl_gf2e.pyx in sage.rings.finite_rings.element_ntl_gf2e.Cache_ntl_gf2e.fetch_int (/home/sage/sage/src/build/cythonized/sage/rings/finite_rings/element_ntl_gf2e.cpp:7212)()
431
432 if number < 0 or number >= self.order():
--> 433 raise TypeError("n must be between 0 and self.order()")
434
435 if isinstance(number, int) or isinstance(number, long):
TypeError: n must be between 0 and self.order()
```

I realize that what I'm doing isn't technically a finite field but idk how else I might get a "number" turned into a polynomial equation.

Any ideas?