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pariError when computing discriminant

asked 2012-08-14 09:58:15 +0200

Leonhard Moosbrugger gravatar image

Consider the following piece of code:

Qx.<x> = PolynomialRing(Rationals())
K = NumberField(x^2+1, 'a')
OOK = K.ring_of_integers()    #K.maximal_order() has same effect
OOa = OOK.extension(x^3+2, 'alpha'); OOa

This returns "Univariate Quotient Polynomial Ring in alpha over Maximal Order in Number Field in a with defining polynomial x^2 + 1 with modulus alpha^3 + 2". Why is this the case? I would have expected it to have the same effect as

Qx.<x> = PolynomialRing(Rationals())
00b = ZZ.extension([x^3+2,x^2+1], 'beta,b'); OOb

Namely, that it returns "Relative Order in Number Field in beta with defining polynomial x^3 + 2 over its base field".

Moreover, and perhaps more interestingly, when one tries to run the command OOa.discriminant() after the first piece of code, "PariError: (5)" is returned. Running the analogous command, OOb.absolute_discriminant() after the second piece of code, one gets -746496. I presume the fact that these two commands return different results is explained in Quotients of Univariate Polynomial Rings when it says

The discriminant of the quotient polynomial ring need not equal the discriminant of the corresponding number field, since the discriminant of a number field is by definition the discriminant of the ring of integers of the number field.

even though we are not computing the discriminant of a number field in the second piece of code. However, why is a pariError returned when trying to compute the discriminant of OOa? Surely this must be somehow linked to the fact that the two blocks of code return completely different things. Is this indeed the case? Any help would be appreciated.

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answered 2014-07-01 18:02:06 +0200

rws gravatar image

With Sage-6.2 I get

sage: OOa.discriminant()

so the PariError seems to be fixed.

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Asked: 2012-08-14 09:58:15 +0200

Seen: 615 times

Last updated: Jul 01 '14