How come abs(x) works?

Eviatar Bach
748 ●15 ●37 ●52

Hello,

I notice that abs is a Python built-in function, but it also works symbolically:

sage: abs(x)
abs(x)
sage: bool(abs(x) == abs_symbolic(x))
True
sage: preparse('abs(x)')
'abs(x)'

What's going on here? Obviously the Python function should not accept a Sage type.

1 Answer

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5242 ●21 ●68 ●112

Obviously the Python function should not accept a Sage type.

Why not? Python's abs calls __abs__, if it exists:

>>> class NotABuiltinClass(object):
...     def __abs__(self):
...         return 'fred'
... 
>>> a = NotABuiltinClass()
>>> abs(a)
'fred'

The wonders of duck typing. :-)

You're like a Python tutorial waiting to happen, @DSM!

kcrisman ( 12 years ago )

You forgot to include a doctest in your code here, very careless...

kcrisman ( 12 years ago )

Ah, I see. I forgot about the existence of `__abs__`.

Eviatar Bach ( 12 years ago )

Please start posting anonymously - your entry will be published after you log in or create a new account.

Asked: 12 years ago

Seen: 680 times

Last updated: Jun 12 '12