notebook questions

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Another (very simple) question when there is a bug in my program in the notebook, the computer wrotes me which line the bug is. But I don't how to find this line with the given number. Is there a line-numerator in the notebook?

Hmm, that is harder. At least for simple examples, the line does seem to be the line I made the mistake in:

for i in range(10):
    print i+1
    print i^2
    a=i[0]
    print a+i

But multicell ones don't seem to be as nice. You may just have to look at the code that causes the problem and find it in your input. We don't have interactive markup (e.g. coloring) yet, because the javascript really slows things down.

def square_sum(a,b):
    return(a*a+b*b)
fname="filename.dat"
fp=open(fname,'w')
for a in range(1000):
    for b in range(1000):
        s=str(a)+' '+str(b)+' '+str(square_sum(a,b))+'\n'
        fp.write(s)
fp.close()

This will write the data to a filename named "filename.dat". You can also give a path if you wish.

To read it from another notebook use the following code

import numpy as np
array=np.genfromtxt('/path-to-file/filename.dat',delimiter='')

Of course you have to replace 'path-to-file' by whatever path it is. Now you can use array the way we usually use arrays.

I hope this helps.

If Sage is the only program that needs to read the data, you can use the "save" and "load" commands:

sage: square_sum = dict(((a,b),a^2+b^2) for a,b in CartesianProduct([1..5],[1..5]))
sage: square_sum 
{(1, 3): 10, (5, 4): 41, (2, 1): 5, (5, 1): 26, (2, 5): 29, (1, 2): 5, (3, 3): 18, (4, 4): 32, (1, 5): 26, (2, 2): 8, (5, 3): 34, (4, 1): 17, (1, 1): 2, (3, 2): 13, (4, 5): 41, (5, 5): 50, (1, 4): 17, (2, 3): 13, (4, 2): 20, (3, 5): 34, (3, 4): 25, (3, 1): 10, (4, 3): 25, (5, 2): 29, (2, 4): 20}
sage: save(square_sum, "ssum")
sage: s2 = load("ssum")
sage: s2
{(1, 3): 10, (3, 2): 13, (2, 1): 5, (5, 1): 26, (2, 5): 29, (1, 2): 5, (3, 3): 18, (4, 4): 32, (1, 5): 26, (2, 2): 8, (3, 5): 34, (4, 1): 17, (1, 1): 2, (5, 4): 41, (4, 5): 41, (1, 4): 17, (2, 3): 13, (4, 2): 20, (5, 5): 50, (5, 3): 34, (5, 2): 29, (3, 1): 10, (4, 3): 25, (3, 4): 25, (2, 4): 20}
sage: s2 == square_sum
True

(Remember that dictionaries don't have an order, so the fact that the keys show up differently in s2 than in the original square_sum doesn't matter.)