Get point coordinates of curve over number field    
   Suppose I have equation of curve C:
curve 
# => y^2 + (x^2 + x)*y + x
curve.parent()
# => Univariate Polynomial Ring in y over Rational function field in x over Rational Field
and I know that there is a point with x value is a root of another equation (i.e. element of corresponding Number Field): 
equation
# => x^3 + x^2 - 2*x - 9/2
equation.parent()
# => Univariate Polynomial Ring in x over Rational Field
is x-coordinate of some point of C.
How to properly get y-coordinate of C in x?
It is not as easy as it seems because of conversion problems.
My workaround is as following:
FF.<z> = NumberField(equation)
P.<x,y> = QQ[]
u = P(curve).subs(x=z)
P.<y> = FF[]
return z, P(u).roots()[0][0]
and it doesn't seem right.
Are there more elegant way of doing it?
P.S. curve is constructed as follows:
  F = FunctionField(QQ, 'x')
  x = F.gen()
  R.<y> = F[]
  curve = y^2 + (x^2 + x)*y + x;
But it was done in another place so I have no direct access to x and y from above code.
 
 
Could you please provide the construction of
curve?@tmonteil, I've added P.S. with details