A couple things to complete the (exact) answer of Sebastien
sqrt(1/z) will give you ONE solution of the equation t^2==1/(1+I). There are two :
sage: solve(t^2==1/(1+I),t)
[t == -sqrt(-1/2I + 1/2), t == sqrt(-1/2I + 1/2)]
You may have a better grasp of the meaning of the answer(s) by asking maxima.polarform(sqrt(1/z)) and maxima.polarform(1/sqrt(z)) respectively :
sage: maxima.polarform(sqrt(1/z))
%e^-((%i*%pi)/8)/2^(1/4)
sage: maxima.polarform(1/sqrt(z))
%e^-((%i*%pi)/8)/2^(1/4)
HTH,
Yikes. That output format for maxima.polarform is pretty ugly (I understand it's standard for maxima). Does Sage not have a simple polarform() function to put a complex number in polar form using a normal symbolic expression?
(FWIW I was able to implement this as abs(z)*exp(arg(z)*I, hold=True) (without the hold it does some deeply unhelpful "simplification"); seems like it would be a worthwhile built-in to have, or at least a method of complex numbers)
I get:
sage: z = 1 + I
sage: sqrt(1/z)
sqrt(-1/2*I + 1/2)
If you want the real and imaginary parts, you may do:
sage: s = sqrt(1/z)
sage: s.real().simplify()
1/4*2^(3/4)*sqrt(sqrt(2) + 2)
sage: s.imag().simplify()
-1/4*2^(3/4)*sqrt(-sqrt(2) + 2)
Asked: 2018-09-08 02:16:57 +0200
Seen: 2,930 times
Last updated: Sep 11 '18
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