1 | initial version |

A couple things to complete the (exact) answer of Sebastien

`sqrt(1/z)`

will give you**ONE**solution of the equation`t^2==1/(1+I)`

. There are two :sage: solve(t^2==1/(1+I),t)

[t == -sqrt(-1/2

*I + 1/2), t == sqrt(-1/2*I + 1/2)]You may have a better grasp of the meaning of the answer(s) by asking

`maxima.polarform(sqrt(1/z))`

and`maxima.polarform(1/sqrt(z))`

respectively :sage: maxima.polarform(sqrt(1/z))

%e^-((%i*%pi)/8)/2^(1/4)

sage: maxima.polarform(1/sqrt(z))

%e^-((%i*%pi)/8)/2^(1/4)

HTH,

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