m = matrix(ZZ, 3, 3, lambda i, j: 1/(i + j) ); m
Sage tells me the following:
Traceback (click to the left of this block for traceback)
...
ZeroDivisionError: rational division by zero
why? it really confused me.
The problem is that matrix rows and columns are numbered from 0.
So the top left element of that matrix would be 1 / (0 + 0).
If you are thinking of rows and columns as numbered from 1, do this instead:
sage: m = matrix(QQ, 3, 3, lambda i, j: 1 / (i + j + 2)); m
[1/2 1/3 1/4]
[1/3 1/4 1/5]
[1/4 1/5 1/6]
or you can use another base ring such as RR or R in your example, if you defined R as a ring beforehand (in Sage, by default, R stand for the interpreter for the R statistics language).
Alternatively, the matrix constructor can get an explicit list of lists (or the flat list associated to this one), instead of a function, and there is no confusion any longer. (Well, also using i will overwrite the default value of this variable in sage, which corresponds to $\sqrt{-1}$, i will use k and n instead of i, j .)
For instance:
sage: [ 1/(k+n) for k in [1..3] for n in [1..3] ]
[1/2, 1/3, 1/4, 1/3, 1/4, 1/5, 1/4, 1/5, 1/6]
sage: [ [ 1/(k+n) for k in [1..3] ] for n in [1..3] ]
[[1/2, 1/3, 1/4], [1/3, 1/4, 1/5], [1/4, 1/5, 1/6]]
sage: matrix( QQ, [ 1/(k+n) for k in [1..3] for n in [1..3] ] ) # bad
[1/2 1/3 1/4 1/3 1/4 1/5 1/4 1/5 1/6]
sage: matrix( QQ, 3, [ 1/(k+n) for k in [1..3] for n in [1..3] ] )
[1/2 1/3 1/4]
[1/3 1/4 1/5]
[1/4 1/5 1/6]
sage: matrix( QQ, 3, 3, [ 1/(k+n) for k in [1..3] for n in [1..3] ] )
[1/2 1/3 1/4]
[1/3 1/4 1/5]
[1/4 1/5 1/6]
sage: matrix( QQ, [ [ 1/(k+n) for k in [1..3] ] for n in [1..3] ] )
[1/2 1/3 1/4]
[1/3 1/4 1/5]
[1/4 1/5 1/6]
sage: matrix( QQ, 3, [ [ 1/(k+n) for k in [1..3] ] for n in [1..3] ] )
[1/2 1/3 1/4]
[1/3 1/4 1/5]
[1/4 1/5 1/6]
sage: matrix( QQ, 3, 3, [ [ 1/(k+n) for k in [1..3] ] for n in [1..3] ] )
[1/2 1/3 1/4]
[1/3 1/4 1/5]
[1/4 1/5 1/6]
Asked: 2017-11-28 15:32:59 +0100
Seen: 683 times
Last updated: Nov 29 '17
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