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# plotting points

How can I show points that I get as the result in line 11? I have that two circles, but I do not know how to get points on the graph.

var('x, y')
ft = (x+1)^2-(y)^2-1
f=circle((-1,0), 1)
p = plot(f,-5,5, thickness=2)

@interact
def _(r=(1..4)):
g = circle((1,0), r)
pt = plot(g,-5, 5, color='green', thickness=2)
gt= (x-1)^2+ y^2-r
pot = solve([ft,gt], x, y)
html('$tocke=\;%s$'%latex(pot))
show(  p + pt, ymin = -5, ymax = 4)

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## Comments

also I don't know why I get four, and not two solutions for points

( 2014-09-30 15:39:54 -0500 )edit

## 1 answer

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var('x, y')
ft = (x+1)^2-(y)^2-1
f=circle((-1,0), 1,thickness=2)

@interact
def _(r=(1..4)):
g = circle((1,0), r,color='green', thickness=2)
gt= (x-1)^2+ y^2-r
pot = solve([ft,gt], x, y,solution_dict=True)
P = []
for L in pot:
try:
P.append(point((L[x],L[y]),color='red',pointsize=20))
except:
pass
html('$tocke=\;%s$'%latex(pot))
show(  f + g + sum(P) , ymin = -5, ymax = 4,aspect_ratio=1)

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## Comments

but it doesn't work for lager r (when r=2,3,4)

( 2014-10-01 01:47:49 -0500 )edit

I made some changes (that I did wrong in pointing out circles), and now your idea for points works perfectly. thank you

( 2014-10-01 02:50:04 -0500 )edit

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Asked: 2014-09-30 14:22:38 -0500

Seen: 176 times

Last updated: Sep 30 '14