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How can I show points that I get as the result in line 11? I have that two circles, but I do not know how to get points on the graph.

var('x, y') ft = (x+1)^2-(y)^2-1 f=circle((-1,0), 1) p = plot(f,-5,5, thickness=2) @interact def _(r=(1..4)): g = circle((1,0), r) pt = plot(g,-5, 5, color='green', thickness=2) gt= (x-1)^2+ y^2-r pot = solve([ft,gt], x, y) html('$tocke=\;%s$'%latex(pot)) show( dot + p + pt, ymin = -5, ymax = 4)

How can I show points that I get as the result in line 11? I have that two circles, but I do not know how to get points on the graph.

var('x, y') y')

ft = (x+1)^2-(y)^2-1 (x+1)^2-(y)^2-1

f=circle((-1,0), 1) 1)

p = plot(f,-5,5, thickness=2) @interact thickness=2)

@interact

def _(r=(1..4)): _(r=(1..4)):

g = circle((1,0), r) r)

pt = plot(g,-5, 5, color='green', thickness=2) thickness=2)

gt= (x-1)^2+ y^2-r y^2-r

pot = solve([ft,gt], x, y) html('$tocke=\;%s$'%latex(pot)) y)

html('$tocke=\;%s$'%latex(pot))

show( dot + p + pt, ymin = -5, ymax = 4)

How can I show points that I get as the result in line 11? I have that two circles, but I do not know how to get points on the graph.

var('x, y')

ft = (x+1)^2-(y)^2-1

f=circle((-1,0), 1)

p = plot(f,-5,5, thickness=2)

@interact

def _(r=(1..4)):

g = circle((1,0), r)

pt = plot(g,-5, 5, color='green', thickness=2)

gt= (x-1)^2+ y^2-r

pot = solve([ft,gt], x, y)

html('$tocke=\;%s$'%latex(pot))

show( dot + p + pt, ymin = -5, ymax = 4)

How can I show points that I get as the result in line 11? I have that two circles, but I do not know how to get points on the graph.

var('x, y')
 
y')
ft = (x+1)^2-(y)^2-1
 
(x+1)^2-(y)^2-1
f=circle((-1,0), 1)
 
1)
p = plot(f,-5,5, thickness=2)thickness=2)
  
@interact
 
@interact
def _(r=(1..4)):
 
_(r=(1..4)):
  g = circle((1,0), r)
 
r)
  pt = plot(g,-5, 5, color='green', thickness=2)
 
thickness=2)
  gt= (x-1)^2+ y^2-r
 
y^2-r
  pot = solve([ft,gt], x, y)
 
html('$tocke=\;%s$'%latex(pot))
 
y)
  html('$tocke=\;%s$'%latex(pot))
  show(  p + pt, ymin = -5, ymax = 4)4)