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Points making up a plot

asked 2014-03-22 21:31:54 -0500

dazedANDconfused gravatar image

I'd like to get the list of points that make up a sage plot so I can process it through LaTeX (eg pgfplots) and get a better looking plot. This post here is essentially what I'm looking. I didn't really understand the code but came up with this:

p = implicit_plot(f(x,y)==3,(x,-3,3),(y,-3,3),plot_points=300)
P = p.matplotlib()
R = P.get_children()[1]
S = R.collections[0]
r = S.get_paths()[0]
v = r.vertices
xvals = v[:,0]
yvals = v[:,1]

Change the function to f(x,y)=x^2+y^2 and the code works properly. But the example above only gives me the list of points for the left half of the hyperbola. How can I get the list of points when the graph is disconnected? Can that be extended to get the list of points if there are multiple graphs in the same plot?

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answered 2014-03-23 05:38:51 -0500

fidbc gravatar image

It seems that the set of points on the right half are in S.get_paths()[1]. So

s = S.get_paths()[1]
w = s.vertices
xvals1 = w[:,0]
yvals1 = w[:,1]

should do the job.

Not sure if other "connected components" would appear as subsequent elements of S.get_paths() but it seems likely.

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Asked: 2014-03-22 21:31:54 -0500

Seen: 128 times

Last updated: Mar 23 '14