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how to correctly plot 1/(x-3)

asked 2011-12-15 22:12:52 -0500

Amit Kumar gravatar image

I have to plot 1/(x-3). clearly the function is not defined at x=3. Whenever I try to plot it there is a huge vertical line at x=3, which should not be there. Help me out.

The code I write sage: f(x)=1/(x-3) sage: p=plot(f(x),(x,-10,10) sage: p.show()

Thanks Amit

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answered 2011-12-16 02:44:41 -0500

Jason Grout gravatar image

updated 2011-12-16 02:45:59 -0500

You can also use the detect_poles option to not draw the vertical line

plot(1/(x-3),(x,0,5), detect_poles=True,ymin=-2,ymax=2)

Or even better, have it automatically draw the asymptote:

plot(1/(x-3),(x,0,5), detect_poles='show',ymin=-2,ymax=2)
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answered 2011-12-15 23:45:38 -0500

Use a plot range in show

p.show(ymin=-2, ymax=2)

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answered 2011-12-16 21:27:29 -0500

Amit Kumar gravatar image

Thanks Jason,tririver and Niles for the help.

especially Jason... Your method is with the least code and effective. Thanks

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You're welcome :) If you want, you can click the check mark to "accept" Jason's answer.

niles gravatar imageniles ( 2011-12-17 15:31:49 -0500 )edit
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answered 2011-12-15 23:39:37 -0500

niles gravatar image

In Sage you can add separate plots to draw them on the same image; try this:

sage: f(x)=1/(x-3)
sage: p=plot(f(x),(x,-10,2.9), aspect_ratio=1)
sage: q=plot(f(x),(x,3.1,10), aspect_ratio=1)
sage: (p+q).show()

or, if you want to be a little fancy, add the asymptote:

sage: L = line2d([(3,10),(3,-10)], linestyle="dashed", color="red")
sage: (p+q+L).show()
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Asked: 2011-12-15 22:12:52 -0500

Seen: 317 times

Last updated: Dec 16 '11