# Can I parse CSV data separated by \t to vectors

I have a CSV data as follows:

```
pcb138 pcb180 pcb52 pcb118 pcb
1.46 0.738 0.532 0.72 19.9959
0.64 0.664 0.03 0.236 6.0996
3.29 1.15 0.134 1.54 24.9655
3.94 1.33 0.466 1.94 37.4436
3.18 2.14 0.243 1.47 30.183
2.43 1.3 0.137 1.31 20.8036
3.94 3.49 0.208 0.876 41.3818
3.38 1.04 0.477 2.46 29.478
2.21 0.966 0.457 1.14 24.2387
2.49 1.59 0.298 1.18 26.3198
0.86 0.395 0.02 0.406 8.591
3.38 1.85 0.539 1.5 36.4229
7.39 4.42 0.707 3.55 66.4108
```

Is it possible to read that to vectors? I tried the following:

```
sage: import csv
sage: file='/home/jaakko/Downloads/pcb.dat'
sage: reader=csv.reader(open(file))
sage: L=[]
sage: for row in reader:^J L.append(row)
....:
sage: L[0][0]
'pcb138\tpcb180\tpcb52\tpcb118\tpcb'
sage: L[1][0]
'1'
sage: L[1][1]
'46\t'
```

What I would like to have is vectors of the form

```
pcb138=vector([1.46,0.64,...,7.39])
```

without those tabulators.