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Polynomial Ring bug?

asked 2013-06-09 05:14:51 -0600

blishko gravatar image

updated 2013-06-09 20:56:09 -0600

I would like to ask, why following code ends with error:


R = PolynomialRing(GF(3),'x3,x5,x4,x7,x6')

U = PolynomialRing(GF(3), 'x2, x5, x4, x1, x0, x6')

f = U.gens()[1] + U.gens()[2]

g = R(f)


because when I remove x0 from the generators, it works fine.


R = PolynomialRing(GF(3),'x3,x5,x4,x7,x6')

U = PolynomialRing(GF(3), 'x2, x5, x4, x1, x6')

f = U.gens()[1] + U.gens()[2]

g = R(f)


Thanks for the answer, but there is still an open question. I have been working with this for a few days, and up untill this case, I had no trouble getting the same polynomial in a ring with fewer genarators, if the original polynomial contained only those. I tried and the followng code works fine, and it also fits your last case which according to you should raise an error, because U has more generators than R.


R = PolynomialRing(GF(3),'x5,x4,x7,x6')

U = PolynomialRing(GF(3), 'x2, x5, x4, x1, x6')

f = U.gens()[1] + U.gens()[2]

g = R(f)

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answered 2013-06-09 15:31:09 -0600

Executing g=R(f) calls the __call__ method for the ring R. You should read the documentation for this (by executing R.__call__?). In summary: given two polynomial rings U and R, if every generator of U is a generator for R, then R(f) does the obvious thing, mapping each generator of U to the generator of R with the same name. Otherwise, if U has at most as many generators as R, then map the ith generator of U to the ith generator of R. Otherwise, U must have more generators, so raise an error. Your case fits into this last situation.

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I edited the question. There is a case that fits your last situation, and it does not raise an error. I would like to know the difference.

blishko gravatar imageblishko ( 2013-06-09 20:57:57 -0600 )edit

Your question is answered in R.__call__? docstring, did you read it?

Volker Braun gravatar imageVolker Braun ( 2013-06-10 04:37:43 -0600 )edit

I did, but I don't see it. Could you point me to the sentence that answers my question?

blishko gravatar imageblishko ( 2013-06-10 20:39:19 -0600 )edit

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Asked: 2013-06-09 05:14:51 -0600

Seen: 87 times

Last updated: Jun 09 '13