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2020-04-17 19:07:14 +0200 | asked a question | Rational parametrization of plane curves. Is this a bug? I am trying to compute the rational parametrization of a plane curve. According to sage is irreducible and has genus 0, hence it should be possible. However, i get the following error Is this a SAGE or a Singular bug or am I missing something? |
2019-11-28 16:37:01 +0200 | asked a question | Check if a curve is a geodesic Suppose you have a curve I tried But it seems to be impossible to compute covariant derivatives of vectors field along curves. Is there any way to do this? |
2019-10-30 14:40:14 +0200 | commented answer | Compute the inverse of a 2-form For the record, one would have to write |
2019-10-30 14:36:36 +0200 | commented answer | Compute the inverse of a 2-form
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2019-10-23 12:39:17 +0200 | asked a question | Compute the inverse of a 2-form I have a nondegenerate (0,2)-tensor I tried |
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2018-02-19 19:45:29 +0200 | asked a question | Create multivariate function of a list of variables I have created a list of variables, I'd like to create a function of those variables, but doesn't work. Of course in my actual code I'm creating is not convenient |
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2016-02-14 23:50:12 +0200 | commented answer | Compute perfect matchings in a graph Thank you. Now I use the Jupyter notebook. It's much easier noticing that mistakes with syntax colouring. |
2016-02-13 00:42:52 +0200 | asked a question | Compute perfect matchings in a graph I am trying to calculate all the perfect matchings of a graph G (i. e., the subgraphs of G such that every two points are connected) But this gives me I don't understand the error (the loop seems fine to me). What's wrong? |
2016-02-04 02:30:48 +0200 | asked a question | Get vector from abelian group I want to represent the Cayley graph of an abelian group (let's say $A=Z_5^2$) is a way that the element $g=a^i b^j$ is in the position $[i,j]$. I need a method How could I do that? |
2016-02-04 02:22:33 +0200 | asked a question | Get abelian group element powers. I have the abelian group (let's say, $Z_5^2$). I want to represent its Cayley graph as a grid, in which the element $a^i b^j$ occupies the $[i,j]$ position in the plane. For that, I need would need a method -->e=aba^-1 --> [0,1] How can I create something like that? |
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2015-10-20 00:57:46 +0200 | asked a question | Grad, Div and Curl in spherical coordinates with SageManifold As eric_g recommended in this post http://ask.sagemath.org/question/2959..., I tried SageManifolds (I had to give up index notation, since the current implementation is still very basic). I tried to derive the formulas for Grad, Div and Curl in spherical coordinates. However, it only worked for Curl. This is my notebook: https://cloud.sagemath.com/projects/4... I don't know what am I doing wrong. Also, I cannot simplify simple expressions such as the one for the divergence. |
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2015-09-26 00:51:23 +0200 | asked a question | Index notation I am taking a course in general relativity, and I was planing to use sage for doing calculations. I have I wanted to calculate $a^{^i,^j}$ Is there some way to tell Sage what is the metric, and do the index lowering automatically? I did it manually, but it's cumbersome for more complicated calculations. Also, I don't know how to compute $vî v_i$, since does not work. Apart from that, I would like to know if there is a way to do this kind of computations with tensor fields and index notation, including derivatives, etc. |
2015-08-27 00:28:51 +0200 | marked best answer | Using interact I want to visualize these functions in the complex plane: $$f_n(z)=\exp(z) - \sum_{k=0}^{n} \frac{z^k}{k!}$$ I tried this code, but it gives me an error. I am new to Sage (I previously used Mathematica). I wrote the code based on this example: http://wiki.sagemath.org/interact/ . How can I fix that? EDIT: I would also like to know why doesn't this work either Then I type myPlot(2) in the notebook, but I get nothing. However, if I type: I get the correct plot. EDIT 2: I tried And now I can evaluate it. However, I still can't use @Interact. This doesn't make sense to me. |