ismon's profile - activity

Yes, I see your point. Thank you.

Although, I hoped that I shouldn't rely on analysis, since I would like to use sage to calculate the answer to compare with my own calculations and analysis. With MATLAB for instance, the answer can be given without doing any analysis.

Is this possible with sage?

Hi!

I'm trying to find the inverse laplace transform from the following equation: (5 * s * e^(-2*s))/(s^2 + 9).inverse_laplace(s,t),

although sage responds with:

ilt((5 * s * e^(-2*s))/(s^2 + 9)).

How do I find the inverse laplace transform from the equation above?

Sincerly Simon

The question is not whether my checklist answers or the output from sage is correct, I know they both are! My question is how to formulate a command in sage so that the result will be of the same form as that in my checklist. It's not a question of getting a correct answer, but of how the output is displayed.

It is the vector that corresponds to a given eigenvalue. It represents the vector by which translation to the same vectorspace can be done by a translation matrix or a eigenvalue. Eigenvectors can generate a basis for the vectorspace, with no higher dimension than the original vectorspace. I'm sorry if the explanation is not all correct, I'm used to discuss linear algebra in danish.

Anyways, how does your question answer mine?

Hi!

I would like to find the complex eigenvectors of this matrix:

A=matrix(CDF,[[2-i,0,i],[0,1+i,0],[i,0,2-i]]).

I have used the command A.eigenvectors_right() and I get the following eigenvectors (rounded off):

(-0.70711+9.4136e-17i , 0 , 0.70711), (0,1,0), (0.70711 , 0 , 0.70711)

In my checklist I should get the vectors: t1(-1,0,1), t2(0,1,0), t3*(1,0,1), where the t-values are complex factors.

How do I compute this kind of result?

Sincerly Simon

Thank you very much for your answer!

I have marked your answer as being the correct answer. I don't know if I am to give you points, but if I am, please reply of how I do this.

Sincerly Simon

Thank you very much for your answer!

Sincerly Simon

Hi there!

In a linear algebra assignment I have the following equation I need to find a solution for:

-2*sqrt(3)*sin(t)^2+2*cos(t)*sin(t)+sqrt(3)==0. I know the result is pi/3.

Now, when I use solve, solve(-2*sqrt(3)*sin(t)^2+2*cos(t)*sin(t)+sqrt(3)==0, t). I get:

[sin(t) == -1/6*sqrt(3)*(sqrt(cos(t)^2+6)-cos(t), sin(t) == 1/6*sqrt(3)*sqrt(cos(t)^2+6)+cos(t))].

How do I use the solve function to get the more simplified result?

NB: I have also tried to use find_root and different simplify functions, but also without any luck. I am new to sage, so it is quite possible that I don't know a specification to the solve function which I should use.

Thank you in advance!

Sincerly Simon