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2015-03-24 08:33:46 +0100 commented answer solving equation involving absolute values


2015-03-24 06:13:43 +0100 asked a question solving equation involving absolute values


I am newbie to sagemath. I have windows 8 and sage version is 6.4.1. I am running it inside virtualbox. I was reading some thing about solving equations on sage website at

At one point author is trying to demonstrate the use of optional keywords for the "solve" He is solving equation

solve(abs(1-abs(1-x)) == 10, x)

When evaluated this gives

[abs(abs(x - 1) - 1) == 10]

But when the input is modified a little as

solve(abs(1-abs(1-x)) == 10, x, to_poly_solve=True)

sage gives correct result as [x == -10, x == 12]

So why does it not work in the first case ? I didn't understand this use of keyword to_poly_solve.

I tried to post this question on sage-support but for some reason my posted question doesn't seem to appear there.

Please help sundar