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2015-03-24 08:33:46 +0100 | commented answer | solving equation involving absolute values thanks.... |

2015-03-24 06:13:43 +0100 | asked a question | solving equation involving absolute values Hello I am newbie to sagemath. I have windows 8 and sage version is 6.4.1. I am running it inside virtualbox. I was reading some thing about solving equations on sage website at http://www.sagemath.org/doc/reference... At one point author is trying to demonstrate the use of optional keywords for the "solve" He is solving equation solve(abs(1-abs(1-x)) == 10, x) When evaluated this gives [abs(abs(x - 1) - 1) == 10] But when the input is modified a little as solve(abs(1-abs(1-x)) == 10, x, to_poly_solve=True) sage gives correct result as [x == -10, x == 12] So why does it not work in the first case ? I didn't understand this use of keyword to_poly_solve. I tried to post this question on sage-support but for some reason my posted question doesn't seem to appear there. Please help sundar |

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