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2011-05-18 17:22:31 -0500 | commented answer | evaluating inverse erf Thanks for the answer (I have something to work with now) and for creating the ticket! |

2011-05-18 17:21:42 -0500 | answered a question | evaluating inverse erf Thanks for the answer (I have something to work with now) and creating the ticket! |

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2011-05-18 03:22:39 -0500 | asked a question | evaluating inverse erf Hi - The code below results in an expression, y, involving the inverse erf function i.e. exp(sqrt(2) inverse_erf(1/2)) which is approximately 1.96 according to another mathematical package. I tried to get a numerical value for y using y.n() but that crashes. Can anyone please advise how to evaluate such symbolic expressions? |

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