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2023-06-25 07:25:01 +0200 | commented question | To find pattern(if it exists) for finite sequences Hmm...Oh...Okay... |
2023-06-25 07:23:01 +0200 | commented question | To find pattern(if it exists) for finite sequences Hmm...Okay. |
2023-06-23 19:10:02 +0200 | commented question | To find pattern(if it exists) for finite sequences Actually, I was thinking if something of the sort https://ask.sagemath.org/question/68486/code-for-guessing-formula-for |
2023-06-22 19:39:35 +0200 | asked a question | To find pattern(if it exists) for finite sequences To find pattern(if it exists) for finite sequences I am working on something in whose outputs I would be getting pairs |
2023-03-04 14:13:52 +0200 | commented answer | Is there a function for negacyclic matrices? Oh Great !. Thanks a lot |
2023-03-04 04:42:38 +0200 | asked a question | Is there a function for negacyclic matrices? Is there a function for negacyclic matrices? I know that circulant matrices are defined in sagemath. I don't know if neg |
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2023-01-08 18:45:02 +0200 | commented answer | How to speed up this code Yes, thanks, I know you have put in a lot of time and efforts. Thanks from the bottom of my heart for all that. Thought |
2023-01-08 16:18:12 +0200 | commented answer | How to speed up this code When I ran the last code you have posted here on this page, in Jupyter and supercomputer got no output and on Sagemath C |
2023-01-08 16:16:58 +0200 | commented answer | How to speed up this code When I ran the last code you have posted here on this page, in Jupyter and supercomputer got no output and on Sagemath C |
2023-01-08 16:16:44 +0200 | commented answer | How to speed up this code When I ran the last code you have posted here on this page, in Jupyter and supercomputer got no output and on Sagemath C |
2023-01-08 16:16:18 +0200 | commented answer | How to speed up this code When I ran the last code you have posted here on this page, in Jupyter and supercomputer got no output and on Sagemath C |
2023-01-08 16:15:24 +0200 | commented answer | How to speed up this code When I ran the last code you have posted here on this page, in Jupyter and supercomputer got no output and on Sagemath C |
2023-01-08 16:14:40 +0200 | commented answer | How to speed up this code When I ran the last code you have posted here on this page, in Jupyter and supercomputer got no output and on Sagemath C |
2023-01-08 16:12:51 +0200 | commented answer | How to speed up this code When I ran the last code you have posted here on this page, in Jupyter and supercomputer got no output and on Sagemath C |
2023-01-08 15:46:53 +0200 | commented answer | How to speed up this code I ran the earlier code(No.6, Revision, second one in Revision History) on Sagemath Console instead of Jupyter notebook |
2023-01-08 15:46:01 +0200 | commented answer | How to speed up this code I ran the earlier code(No.6, Revision, second one in Revision History) on Sagemath Console instead of Jupyter notebook |
2023-01-08 15:45:19 +0200 | commented answer | How to speed up this code I ran the earlier code(No.6, Revision, second one in Revision History) on Sagemath Console instead of Jupyter notebook |
2023-01-08 15:44:42 +0200 | commented answer | How to speed up this code I ran the earlier code(No.6, Revision, second one in Revision History) on Sagemath Console instead of Jupyter notebook |
2023-01-08 15:44:15 +0200 | commented answer | How to speed up this code I ran the earlier code(No.6, Revision, second one in Revision History) on Sagemath Console instead of Jupyter notebook |
2023-01-05 16:32:46 +0200 | commented answer | How to speed up this code Yes, your first code was indeed very good and fast, as I have mentioned in my very first comment. I am getting the same |
2023-01-05 14:43:32 +0200 | commented answer | How to speed up this code What could be possible reasons behind vast diifference between your output and mine? What to do now? |
2023-01-05 14:09:03 +0200 | commented answer | How to speed up this code As I have mentioned in my previous two comments, I have taken M as follows:` M = matr |
2023-01-05 14:07:50 +0200 | commented answer | How to serially number the output ? As I have mentioned in my previous two comments, I have taken M as follows:` M = matr |
2023-01-05 14:07:38 +0200 | commented answer | How to serially number the output ? As I have mentioned in my previous two comments, I have taken M as follows: M = ma |
2023-01-05 13:56:54 +0200 | commented answer | How to speed up this code My input and output for M = matrix(2, 2, [1, 1, 1, -1]) are as follows: πΌ=(111β1) Enter the order o |
2023-01-05 13:50:37 +0200 | commented answer | How to speed up this code My input and output are as follows: πΌ=(111β1) Enter the order of the matrix M: 2 In how m |
2023-01-05 13:49:06 +0200 | commented answer | How to speed up this code The input and output are as follows: πΌ=(111β1) Enter the order of the matrix M: 2 In how |
2023-01-05 13:47:42 +0200 | commented answer | How to serially number the output ? The input and output are as follows: πΌ=(111β1) Enter the order of the matrix M: 2 In how |
2023-01-05 13:47:31 +0200 | commented answer | How to serially number the output ? The input and output are as follows: πΌ=(111β1) Enter the order of the matrix M: 2 |
2023-01-05 13:46:17 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:45:58 +0200 | commented answer | How to serially number the output ? Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 How many matr |
2023-01-05 13:45:14 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:45:00 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:44:41 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:44:25 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:44:04 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:43:52 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:43:34 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:43:18 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:43:09 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:43:00 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:42:39 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:42:13 +0200 | commented answer | How to serially number the output ? πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want to break M: 4 |
2023-01-05 13:41:54 +0200 | commented answer | How to serially number the output ? enter co πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want t |
2023-01-05 13:40:06 +0200 | commented answer | How to serially number the output ? enter co πΌ=(111β1) Enter the order of the matrix M: 2 In how many matrices you want t |