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With the accepted answer, I can do view(a == sols[0][a]) which is what I meant.

Given the following:

a = var('a')
b = var('b')
c0 = var('c0')
c1 = var('c1')

eq1 = a==exp(b)
eq2 = b==4*c0+2*c1


solve([eq1, eq2], a, b, c0, c1, solution_dict=True)

[{a: e^r5, b: r5, c0: r6, c1: 1/2*r5 - 2*r6}]

I'd like extract a and have something similar to what I would have if I did: view(a==exp(4*c0+2*c1)).

How can I isolate and print term Given the following: a = var('a') b = var('b') c0 = var('c0') c1 = var('c1') eq1 = a=