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2020-03-16 14:54:52 +0200 | asked a question | Strange behaviour with distributivity of multiplication I got the following code wich is not consistent. There should be a bug in there. The priority of the parenthesis is not respected in the first case. |
2020-03-12 14:07:01 +0200 | commented answer | How to solve numericaly with arbitrary precision Dichotomy solve the problem although my function is too much unsmooth to be used so I will stop trying. My function was taking those value: (f(37) was returning 0, but when I used a better resolution it was more 1e67) |
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2020-03-09 17:13:21 +0200 | commented answer | How to solve numericaly with arbitrary precision So Then gives f a very long runtime, find_root don't converge on a reasonable time and while f has a much faster runtime, throw an exception |
2020-03-09 17:11:11 +0200 | commented answer | How to solve numericaly with arbitrary precision Thank you for answering. I have a matrix of hyperbolic and trigonometric function of a variable, I want to know for which values of the variable the matrix is singular. It is analog to the physics problem of knowing the natural frequencies of an oscillator. Although my matrix is not very dense, it is dense enough so that the determinant can't be computed in the symbolic ring. I have to use a lambda function to substitute de variable by its value, change the matrix to the real ring then compute the determinant (the computation of the determinant is too slow if I stay in the symbolic ring). Which is the lambda function I write on my first message with RRR a custom Real Field with 200 bits precision. A code example will follow in the next message |
2020-03-09 14:46:04 +0200 | asked a question | How to solve numericaly with arbitrary precision Hello, I want to solve a numerical equation for which I can only access by a lambda function, the M matrix is to big for the determinant to be computed on the symbolic ring. But , find-root solve in the built in float type of Python which is lacking the precision I need. Is there a way in sage to solve numericaly with arbitrary precision? Thank you Regards (edited with example more in line with what I am trying to achieve) |