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2020-02-13 23:47:17 +0100	received badge	● Supporter (source)
2020-02-13 23:46:52 +0100	commented answer	Acess bracked elements in free lie algebra element? I went ahead and posted a topic on sage-devel here. Your code works but there is still some unfortunate behavior, namely `sage: a_tree._right == x1 False` which can be worked around via something like `sage: a_tree._right == x1.list()[0][0] True` Just paying careful attention to which objects are Lyndon basis elements and which are the binary trees. This has worked for my code but it would be way nicer if there was a cleaner way.
2020-02-13 23:02:36 +0100	received badge	● Nice Question (source)
2020-02-13 11:17:36 +0100	received badge	● Student (source)
2020-02-13 08:39:35 +0100	asked a question	Acess bracked elements in free lie algebra element? I'm trying to access the left and right elements in a free lie algebra element, whose monomials are stored as binary trees. Thus I want a method (like exists in the source for lie_algebra_element) which would return something like `sage: L = LieAlgebra(QQ, 3, 'x') sage: x0,x1,x2 = L.gens() sage: Lyn = FL.Lyndon() sage: a = Lyn.graded_basis(3)[2]; a [[x0, x1], x1] sage: a._left [x0,x1] sage: a._right x1` Of course the last 4 lines are fake. One way of seeing this is the following: `sage: isinstance(a, LyndonBracket) False sage: isinstance(a, LieBracket) False` How do I fix this "the right way" ? My current solution is just to set `sage: a_tree = eval(repr(a)); a_tree [[x0, x1], x1]` But this feels extremely wrong.
2020-02-13 08:39:35 +0100	asked a question	How to access tree information from Free Lie Algebra elements? I'm trying to access the left and right elements in a free lie algebra element, whose monomials are stored as binary trees. Thus I want a method (like exists in the source for lie_algebra_element) which would return something like `sage: L = LieAlgebra(QQ, 3, 'x') sage: sx0,x1,x2 = L.gens() sage: Lyn = FL.Lyndon() sage: a = Lyn.graded_basis(3)[2]; a [[x0, x1], x1] sage: a._left [x0,x1] sage: a._right x1` Of course the last 4 lines are fake. One way of seeing this is the following: `sage: isinstance(a, LyndonBracket) False sage: isinstance(a, LieBracket) False` How do I fix this "the right way" ? My current solution is just to set `sage: a_tree = eval(repr(a)); a_tree [[x0, x1], x1]` But this feels extremely wrong.