2024-07-24 22:02:15 +0200 | commented question | Pickling error with multiprocessing Have you tried to use built-in Sage's parallel computing functionality? https://doc.sagemath.org/html/en/reference/paral |
2024-07-23 17:20:42 +0200 | commented question | Pickling error with multiprocessing Your code works fine in Sagecell |
2024-07-21 00:52:07 +0200 | answered a question | convert symbolic matrix to numeric one You can perform substitution in each element: M.apply_map(lambda t: t.subs(subsdict)) |
2024-07-20 09:36:48 +0200 | received badge | ● Nice Answer (source) |
2024-07-19 20:59:17 +0200 | answered a question | An Exercicse from A=B Function $r(n,k)$ and thus $g(n,k)$ can be computed from $f(n,k)$ as follows: var('k n') f(n,k) = factorial(n)^4 / fact |
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2024-07-16 22:25:32 +0200 | commented question | How to use GF() on a very large finite field ? For a composite, which is not a prime power, one can try to work in the corresponding ring defined via Zmod(). |
2024-07-16 19:48:01 +0200 | commented question | How to use GF() on a very large finite field ? Can you illustrate the issue with an actual code example? |
2024-07-15 20:55:17 +0200 | commented question | Does there exists any simple connected graph $G$ of order $n$, such that whenever $\dfrac{\lambda}{k}$ is an eigenvalue of the adjacency matrix of $G$ See code for a similar problem at https://ask.sagemath.org/question/59220/ |
2024-07-05 14:51:20 +0200 | commented question | About Grobner basis When the number of solutions is finite, you can get them by calling .variety() method of the ideal. Unfortunately, this |
2024-07-05 14:43:41 +0200 | commented question | Finding integer solutions to systems of polynomial equations There may be infinitely many solutions to your equation. What kind of answer do you expect in that case? |
2024-07-02 19:06:22 +0200 | commented question | mini-AES inconsistent implementation between v4.5.1 and v10.3 It's https://github.com/sagemath/sage/issues/38298 |
2024-07-02 19:05:24 +0200 | commented answer | get the coefficients from the polynomial of several variables One can avoid specifying n at all by using InfinitePolynomialRing. |
2024-07-02 11:02:16 +0200 | commented answer | Trouble with subs Please update your question with more details, or better ask a new one. |
2024-07-02 11:02:04 +0200 | commented answer | Trouble with subs Please update your question with more details, better ask a new one. |
2024-07-01 16:56:31 +0200 | commented answer | Trouble with subs That's because your substitutions are inconsistent with each other: multiplying E*E==-1/6, L*L==-1/2, gives E*E*L*L==1/1 |
2024-07-01 16:55:57 +0200 | commented answer | Trouble with subs That's because your substitutions are inconsistent with each other: multiplying E*E==-1/6, L*L==-1/2, gives E*E*L*L==1/1 |
2024-07-01 16:55:42 +0200 | commented answer | Trouble with subs That's because your substitutions are "inconsistent": multiplying E*E==-1/6, L*L==-1/2, gives E*E*L*L==1/12; however mul |
2024-07-01 16:53:48 +0200 | commented answer | Trouble with subs That's because your substitutions are "inconsistent": multiplying E*E==-1/6, L*L==-1/2, gives E*E*L*L==1/12; however mul |
2024-07-01 15:56:13 +0200 | edited question | how to display the list of all monomials occurring in a polynomial how to display the set of all monomials occurring in a polynomial let $f=x+y+z+xy$, how to display the list of all monom |
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2024-07-01 12:14:12 +0200 | edited question | get the coefficients from the polynomial of several variables get the coefficients from the polynomial of several variables I have a polynomial $p(x)=[(x_1-x_2)(x_1-x_3)(x_1-x_4)(x_2 |
2024-07-01 12:13:59 +0200 | edited question | get the coefficients from the polynomial of several variables get the coefficients from the polynomial of several variables I have a polynomial $p(x)=\[(x_1-x_2)(x_1-x_3)(x_1-x_4)(x_ |
2024-07-01 12:06:45 +0200 | edited question | get the coefficients from the polynomial of several variables get the coefficients from the Polynomial polynomial of several variables I have a polynomial $p(x)=(x_1-x_2)(x_1-x_3)(x_ |
2024-07-01 10:40:43 +0200 | answered a question | get the coefficients from the polynomial of several variables Like this: K.<x_1,x_2,x_3,x_4> = QQ[] p = (x_1-x_2)*(x_1-x_3)*(x_1-x_4)*(x_2-x_3)*(x_2-x_4)*(x_3-x_4)^18*(x_1^2+x |
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2024-06-28 18:29:16 +0200 | answered a question | Replacing an expression by another in the ring of polynomials f % (x*y^2 - z) will do the job: K.<x,y,z> = ZZ[] f = x*y^2 + x + y + z print( f % (x*y^2 - z) ) |
2024-06-28 15:59:10 +0200 | received badge | ● Good Answer (source) |
2024-06-28 12:18:51 +0200 | commented answer | Trouble with subs Yes, they are commutative. |
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2024-06-28 07:45:29 +0200 | commented question | mini-AES inconsistent implementation between v4.5.1 and v10.3 Please report the issue at https://github.com/sagemath/sage/issues |
2024-06-28 07:43:12 +0200 | edited answer | Trouble with subs One can have a better control such substitutions using polynomial machinery, reducing a polynomial modulo the ideal gene |
2024-06-28 07:40:33 +0200 | answered a question | Implementing characters inside the function It is always a good idea to avoid generic symbolic ring in favor of more specific classes, which typically provide rich |
2024-06-28 07:19:11 +0200 | answered a question | Computing the time of execution You can use time module for that purpose - like this: import time start_time = time.time() # ...whatever code... end_t |
2024-06-28 07:15:03 +0200 | edited answer | Trouble with subs One can have a better control such substitutions using polynomial machinery, reducing a polynomial modulo the ideal gene |
2024-06-28 07:14:29 +0200 | answered a question | Trouble with subs One can have a better control such substitutions using polynomial machinery, reducing a polynomial modulo the ideal gene |
2024-06-25 17:03:29 +0200 | edited question | "==" with symbolics is doing unwanted boolean comparison "==" with symbolics is doing unwanted boolean comparison parameters var('v0 t', domain='positive') generic funtions |
2024-06-25 16:41:33 +0200 | answered a question | Ordering a list of triplets according to lexical order Lexicographic order is the default one for tuples. So, you can simply use sorted() function or .sort() method on your li |
2024-06-25 16:38:17 +0200 | answered a question | "==" with symbolics is doing unwanted boolean comparison It is convenient to keep equations in the form expression == 0 and furthermore functions dealing with equations will typ |
2024-06-25 16:25:50 +0200 | commented question | Error: trying to find the normal subgroups of a given group The thing is that group-theoretic functionality is implemented at large for permutation groups only (via GAP). So, you m |
2024-06-25 16:25:20 +0200 | commented question | Error: trying to find the normal subgroups of a given group The thing is that group-theoric functionality is implemented at large for permutation groups only (via GAP). So, you may |
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2024-06-23 18:11:52 +0200 | answered a question | Generating two integers with conditions This question has nothing to do with Sage, and furthermore what is asked is impossible. We have $\log_N(2^{58}) \leq \al |
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2024-06-20 02:11:43 +0200 | commented answer | Generate a random integer with some condition It depends on the type of condition. Any modular condition can be treated similarly to what's done in my answer. |
2024-06-20 02:06:29 +0200 | commented answer | Generate a random integer with some condition What specific condition? |
2024-06-20 01:42:15 +0200 | answered a question | Generate a random integer with some condition $3e\equiv 1\pmod5$ means that $e=5k+2$ for some $k$. Then $e$ having $n=71$ bits means $e\in[2^{n-1},2^n-1]$, which tran |