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2019-12-05 23:50:40 +0100 asked a question Equation in complex numbers

I need to solve the following equation.

solve(z^2 == (1-sqrt(3)*I)*z.conjugate(), z)

Sage says

[z == -sqrt((-I*sqrt(3) + 1)*conjugate(z)), z == sqrt((-I*sqrt(3) + 1)*conjugate(z))]

I'd like to get solutions in polar form, something like

[z == 0, z == 2*e^(pi*I/9), z == 2*e^(7*pi*I/9), z == 2*e^(13*pi*I/9)]

Or I'd like to get the absolute values and arguments of the solutions. Is it possible in Sage?

2019-01-25 20:03:29 +0100 commented answer Binary relations

I accepted your answer to this question, but I cannot believe something studied in every first year Discrete Math course is not a part of Sage.

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2019-01-17 13:24:56 +0100 asked a question Binary relations

Are finite binary relations as subsets of Cartesian product implemented in Sage? I am interested in taking set-theoretic operations, finding composition and inverse, checking properties such as reflexivity and antisymmetry. I found a report here, but I am not sure if it made its way into version 8.5. If so, is there documentation and examples? By doing search_src("binaryrelation") I also found functions IsBinaryRelation, IsReflexiveBinaryRelation, etc. in libs/gap/, but I am not sure how to use them.

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2019-01-09 21:04:40 +0100 commented answer How to format posts on this forum?

Thanks. Is there a way to see how other people typed their posts? For now at least I don't have the "edit" button under your post, for example.

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2019-01-08 23:05:50 +0100 asked a question How to format posts on this forum?

Is there a description of features used to format posts on this forum? Does it use Markdown? In particular, I am interested in rules for typing logs of interaction with Sage.

2019-01-08 23:05:49 +0100 asked a question Quadratic equation with complex coefficients

How can I solve x^2 - (1 + I)*x + 6 + 3*I == 0 to get answers z = 3*I and z = 1 - 2*I ? When I enter

solve(x^2 - (1 + I)*x + 6 + 3*I == 0, x)

I get

[x == -1/2*sqrt(-10*I - 24) + 1/2*I + 1/2, x == 1/2*sqrt(-10*I - 24) + 1/2*I + 1/2]