ceee's profile - activity

2020-07-16 21:59:08 +0100	received badge	● Student (source)
2020-04-24 15:54:41 +0100	received badge	● Famous Question (source)
2019-03-08 21:24:10 +0100	received badge	● Notable Question (source)
2017-04-03 16:32:51 +0100	received badge	● Popular Question (source)
2017-03-20 12:17:13 +0100	commented answer	Substituting variable/function Thank you! My lack of understanding was the difference between P and 'p'. This helped a lot
2017-03-20 12:15:07 +0100	received badge	● Scholar (source)
2017-03-19 22:26:09 +0100	asked a question	Substituting variable/function I got a problem with substituting a solution into another equation. I could break down my problem to a simple example: `r = var('r'); p = function('p')(r); v = var('v'); v = p + p.derivative(r); p1(r)=desolve(p.derivative(r)==0,p,ivar=r); p1(r) v.subs(p(r)==p1)` Output: `_C _C + diff(p(r), r)` What's happening here? Why is p substituted, but not diff(p,r)=0? What's the correct way to do this substitution?