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2017-03-20 12:17:13 +0200	commented answer	Substituting variable/function Thank you! My lack of understanding was the difference between P and 'p'. This helped a lot
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2017-03-19 22:26:09 +0200	asked a question	Substituting variable/function I got a problem with substituting a solution into another equation. I could break down my problem to a simple example: `r = var('r'); p = function('p')(r); v = var('v'); v = p + p.derivative(r); p1(r)=desolve(p.derivative(r)==0,p,ivar=r); p1(r) v.subs(p(r)==p1)` Output: `_C _C + diff(p(r), r)` What's happening here? Why is p substituted, but not diff(p,r)=0? What's the correct way to do this substitution?