Alan Moraes's profile - activity

Thanks for the reply, ppurka.

Thanks for the reply, ppurka. This seems to be a good opportunity to learn Lisp :-)

Hi,

For the code below

var('x')

eq1 = x == 0

eq2 = x != 0

solve([eq1, eq2], x)

I get the solution

[[x == 0, 0 != 0]]

I was expecting an empty solution because I guess there isn't a solution to my equations.

Is there a way to avoid such "impossible solutions" and get an empty solution instead?

Thanks