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| 2016-02-19 22:11:41 +0200 | asked a question | The degree of a poynomial in a quotient ring Hello, I am defining a ring, R, two polynomials, p1 and p2, an ideal, I=<p1>, the quotient ring S=R/I, and then I compute p2 in the new ring: sage: R.<x,y>=QQ[] sage: p1=x-y sage:p2=x^2+y^2 sage: I=ideal(p1) sage: S=R.quotient_ring(I) sage: q=p2.change_ring(S) sage: q 2*ybar^2 When I compute the degree of q I get: sage: d=q.degree() sage: d 0 and I want to get d=2. Can anybody tell me how can I obtain d=2? |
Copyright Sage, 2010. Some rights reserved under creative commons license. Content on this site is licensed under a Creative Commons Attribution Share Alike 3.0 license.