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Sorry for the late reply. Yes, this works. Thanks!

I have the polynomials of a certain Eisenstein series. Those are given in the following way:

var('q','z');
K.<sqrt5> = QuadraticField(5);
d2 = [(0, 0, 1), (1/10*sqrt5 + 1/2, 0, 30), (1/10*sqrt5 + 1/2, -1/5*sqrt5 - 1, 1), (1/10*sqrt5 + 1/2, 1/5*sqrt5 + 1, 1), (1/10*sqrt5 + 1/2, -3/10*sqrt5 - 1/2, 12), (1/10*sqrt5 + 1/2, 3/10*sqrt5 + 1/2, 12), (1/10*sqrt5 + 1/2, -1/10*sqrt5 - 1/2, 20), (1/10*sqrt5 + 1/2, 1/10*sqrt5 + 1/2, 20), (1/10*sqrt5 + 1/2, 1/5*sqrt5, 12), (1/10*sqrt5 + 1/2, -1/5*sqrt5, 12), (-1/10*sqrt5 + 1/2, 0, 30), (-1/10*sqrt5 + 1/2, -1/10*sqrt5 - 1/2, 12), (-1/10*sqrt5 + 1/2, 1/10*sqrt5 + 1/2, 12), (-1/10*sqrt5 + 1/2, 1/10*sqrt5 - 1/2, 12), (-1/10*sqrt5 + 1/2, -1/10*sqrt5 + 1/2, 12), (-1/10*sqrt5 + 1/2, 2/5*sqrt5, 1), (-1/10*sqrt5 + 1/2, -2/5*sqrt5, 1), (-1/10*sqrt5 + 1/2, 1/5*sqrt5, 20), (-1/10*sqrt5 + 1/2, -1/5*sqrt5, 20), (-1/5*sqrt5 + 1, 0, 60), (-1/5*sqrt5 + 1, -1, 20), (-1/5*sqrt5 + 1, 1, 20), (-1/5*sqrt5 + 1, -3/10*sqrt5 - 1/2, 20), (-1/5*sqrt5 + 1, 3/10*sqrt5 + 1/2, 20), (-1/5*sqrt5 + 1, -1/10*sqrt5 - 1/2, 60), (-1/5*sqrt5 + 1, 1/10*sqrt5 + 1/2, 60), (-1/5*sqrt5 + 1, 1/10*sqrt5 - 1/2, 60), (-1/5*sqrt5 + 1, -1/10*sqrt5 + 1/2, 60), (-1/5*sqrt5 + 1, 3/10*sqrt5 - 1/2, 20), (-1/5*sqrt5 + 1, -3/10*sqrt5 + 1/2, 20), (-1/5*sqrt5 + 1, 2/5*sqrt5, 30), (-1/5*sqrt5 + 1, -2/5*sqrt5, 30), (-1/5*sqrt5 + 1, 1/5*sqrt5, 60), (-1/5*sqrt5 + 1, -1/5*sqrt5, 60), (1/5*sqrt5 + 1, 0, 60), (1/5*sqrt5 + 1, -2/5*sqrt5 - 1, 20), (1/5*sqrt5 + 1, 2/5*sqrt5 + 1, 20), (1/5*sqrt5 + 1, -1/5*sqrt5 - 1, 30), (1/5*sqrt5 + 1, 1/5*sqrt5 + 1, 30), (1/5*sqrt5 + 1, 1/2*sqrt5 + 1/2, 20), (1/5*sqrt5 + 1, -1/2*sqrt5 - 1/2, 20), (1/5*sqrt5 + 1, -3/10*sqrt5 - 1/2, 60), (1/5*sqrt5 + 1, 3/10*sqrt5 + 1/2, 60), (1/5*sqrt5 + 1, -1/10*sqrt5 - 1/2, 60), (1/5*sqrt5 + 1, 1/10*sqrt5 + 1/2, 60), (1/5*sqrt5 + 1, 1/10*sqrt5 - 1/2, 20), (1/5*sqrt5 + 1, -1/10*sqrt5 + 1/2, 20), (1/5*sqrt5 + 1, 1/5*sqrt5, 60), (1/5*sqrt5 + 1, -1/5*sqrt5, 60), (-2/5*sqrt5 + 1, 0, 30), (-2/5*sqrt5 + 1, 1/5*sqrt5 - 1, 1), (-2/5*sqrt5 + 1, -1/5*sqrt5 + 1, 1), (-2/5*sqrt5 + 1, 1/10*sqrt5 - 1/2, 20), (-2/5*sqrt5 + 1, -1/10*sqrt5 + 1/2, 20), (-2/5*sqrt5 + 1, 3/10*sqrt5 - 1/2, 12), (-2/5*sqrt5 + 1, -3/10*sqrt5 + 1/2, 12), (-2/5*sqrt5 + 1, 1/5*sqrt5, 12), (-2/5*sqrt5 + 1, -1/5*sqrt5, 12), (-2/5*sqrt5 + 1, 0, 30), (-2/5*sqrt5 + 1, 1/5*sqrt5 - 1, 1), (-2/5*sqrt5 + 1, -1/5*sqrt5 + 1, 1), (-2/5*sqrt5 + 1, 1/10*sqrt5 - 1/2, 20), (-2/5*sqrt5 + 1, -1/10*sqrt5 + 1/2, 20), (-2/5*sqrt5 + 1, 3/10*sqrt5 - 1/2, 12), (-2/5*sqrt5 + 1, -3/10*sqrt5 + 1/2, 12), (-2/5*sqrt5 + 1, 1/5*sqrt5, 12), (-2/5*sqrt5 + 1, -1/5*sqrt5, 12), (1, 0, 72), (1, -1/5*sqrt5 - 1, 30), (1, 1/5*sqrt5 + 1, 30), (1, -1, 12), (1, 1, 12), (1, 1/2*sqrt5 + 1/2, 12), (1, -1/2*sqrt5 - 1/2, 12), (1, -3/10*sqrt5 - 1/2, 60), (1, 3/10*sqrt5 + 1/2, 60), (1, -1/10*sqrt5 - 1/2, 60), (1, 1/10*sqrt5 + 1/2, 60), (1, 1/10*sqrt5 - 1/2, 60), (1, -1/10*sqrt5 + 1/2, 60), (1, 2/5*sqrt5, 30), (1, -2/5*sqrt5, 30), (1, 1/5*sqrt5, 60), (1, -1/5*sqrt5, 60)] 
e2 = sum(factor * q**exponent * z**exp2 for exponent,exp2, factor in d2) 

For example, the first entry in the list d2 would give me the entry 1q^0z^0 with the coefficient 1 and the index (0,0). Now I would like to filter these kind of polynomials to find the coefficients of a certain index.
My naive initial idea was to use the method (e2).coefficients() and then search via comparison.The problem that I am having is that I cannot "compare" the values of the index via "==" since the types are not compatible. So, this for example

type(p.coefficients()[1][1])

yields "<class 'sage.symbolic.expression.expression'="">" and I cannot compare this to an expression like "-2*sqrt(1/5) + 1".

Where is my mistake and is there an easy fix to this? Thanks in advance!

This one: e2 = sum(factor * q**exponent * z**exp2 for exponent,exp2, factor in d2). The program tries to fit this into a

This one: e2 = sum(factor * qexponent * zexp2 for exponent,exp2, factor in d2). The program tries to fit this into a rat

Hey Max, thanks. I tried this. But I get the following error message: ... TypeError: Unable to coerce 1/10*sqrt5 + 1/2 t

Type Conversion in coefficient method I have the polynomials of a certain Eisenstein series. Those are given in the foll

Type Conversion in coefficient method I have the polynomials of a certain Eisenstein series. Those are given in the foll

Type Conversion in coefficient method I have the polynomials of a certain Eisenstein series. Those are given in the foll

Type Conversion in coefficient method I have the polynomials of a certain Eisenstein series. Those are given in the foll

Type Conversion in coefficient method I have the polynomials of a certain Eisenstein series. Those are given in the foll

Type Conversion in coefficient method I have the polynomials of a certain Eisenstein series. Those are given in the foll

Thanks a lot to you and Peter for your helpful comments!

I found the following page to calculate one solution for a binary quadratic form $ax^2+bxy +cy^2$: Link

Is there an algorithm to find, if possible, all integer solutions?

Finding all integer solutions of binary quadratic form I found the following page to calculate one solution for a binary

I see what you mean. There seems to be an error in the definition that I was given. Thanks. I will delete this question,

Sorry for the additional question, since Inever got a proper introduction into SAGE: How would I epress the sum $ \sum_{

How to find all elements of a ring up to a certain norm? I am having trouble finding a solution for this very simple que

How to find all elements of a ring up to a certain norm? I am having trouble finding a solution for this very simple que

Sorry for the additional question, since Inever got a proper introduction into SAGE: How would I epress the sum $ \sum_{

Sorry for the additional question, since Inever got a proper introduction into SAGE: How would I epress the sum $ \sum_{

Sorry for the additional question, since Inever got a proper introduction into SAGE: How would I epress the sum $ \sum_{

Sorry for the additional question, since Inever got a proper introduction into SAGE: How would I epress the sum $ \sum_{

Sorry for the additional question, since Inever got a proper introduction into SAGE: How would I epress the sum $ \sum_{

Sorry for the additional question, since Inever got a proper introduction into SAGE: How would I epress the sum $\sum_{r

Sorry for the additional question, since Inever got a proper introduction into SAGE: How would I epress the sum $\sum_{r

Sorry for the additional question, since Inever got a proper introduction into SAGE: How would I epress the sum $\sum_{r

How to find all elements of a ring up to a certain value? I am having trouble finding a solution for this very simple qu

Good question! I meant up to a certain norm, just edited my initial question.

Good question! I meant up to a certain norm.

How to find all elements of a ring up to a certain value? I am having trouble finding a solution for this very simple qu

How to find all elements of a ring up to a certain value? I am having trouble finding a solution for this very simple qu

Is there a way to compute the values of the following special kind of Dedekind Zeta Function:

Assume $a,b \in \mathbb N$ and $K = \mathbb Q(\sqrt{5}) \subset L= \mathbb Q(\sqrt{a+b\sqrt{5}})$. Set $d = \sqrt{a+b\sqrt{5}}$ which is also totally negative and furthermore a discriminant of L.

Now my problem is, can I calculate the (exact or numerical) values of the Dedekind Zeta function $\zeta_L(s)$ for s positive odd integer?

Thanks for any help!

Hi dan, thanks a lot for your answer! This is very helpful!

Special value of Dedekind Zeta Functions Is there a way to compute the values of the following special kind of Dedekind

Hey rburing, thanks for your feedback. This sounds correct, but I am still not sure on how to find the ideal in general.

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Finding divisor and certain ideals Hey SAGE-Community, I am new to SAGE and looking for some help for a small universit