### How to get an arbitrary orientation of a graph.

**I'VE COMPLETELY REVISED MY QUESTION**

I wish to take a simple undirected graph (i.e. the complete graph K_4)
Arbitrarily direct said graph, and then create a line graph from the directed version of the graph.

However, in Sage it appears to create a line graph that shows a connection between two edges (that are just inverses of each other), so what I really want is a line graph that doesn't give an edge connected to its own inverse.

**That's why I asked if we could remove cycles of length 2, but that doesn't seem to solve the problem.**

Here's what I am trying to work out:

```
G = graphs.RandomGNP(4,1)
GD = G.to_directed() #orients G
m = GD.size() #number of edges of digraph GD
LG = GD.line_graph() #the line graph of the digraph
IM = identity_matrix(QQ,GD.size())
T = LG.adjacency_matrix()#returns the adjacency matrix of the line graph
var('u') #defines u as a variable
X=IM-u*T #defines a new matrix X
Z=X.det() #defines polynomial in u aka inverse of the Ihara zeta function
Z #computes determinant of X
Z.coefficients(u) #extracts coefficients
```

considering my graph is a complete graph on 4 vertices - the coefficients should be as such:

[coeff,degree of u]

[1,0], [0,1], [0,2],[-8,3],[-2,4]

**NOTE:**

im only interested in coefficients up to the order of n=#of nodes in the graph, so here for K_4 obviously n=4.

where the coefficient of u^3 corresponds to the negative of twice the number of triangles in K_4

where the coefficient u^4 corresponds to the negative of twice the number of squares in K_4

**Here is an image of a K_4 graph minus an edge and the line graph construction of K_4 that i want**