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### preparser state for regexs

I would have expected the following to work:

reset()
import re

preparser(False)                         # preparser off else we have \\ instead of \
rx=re.compile(r".*(\sHun\s).*")          # in the regex

m = rx.match(r"The Attila the Hun Show") # Find "Hun" in "The Attila the Hun Show"
if m: print "found =>", m.group(1)       # 1 needs to be 1 not '1' here!

preparser(True)


In fact I get 'IndexError: no such group'. Using int(1) fixes the problem, but why? The preparser is off!

Even more curious the block works, as is, on every other evaluate! I tried moving the preparser(False) statement to before the import, but that makes no difference.