# Revision history [back]

### Why does @parallel change my outputs?

Can someone explain this behavior to me:

sage: @parallel
....: def foo(n):
....:         return str(factor(n))
....:
sage: foo(10)
'2 * 5'
sage: for x in foo([1..10]):
....:         print x[0][0][0]
....:
1
2
3
4
5
6
7
8
9
10


I expected to get the factorizations of 1 .. 10, not the numbers 1 .. 10. It seems like the output of foo() is getting evaluated somehow when it goes through the @parallel decorator. Is this a bug?

 2 retagged tmonteil 20703 ●25 ●146 ●382 http://wiki.sagemath.o...

### Why does @parallel change my outputs?

Can someone explain this behavior to me:

sage: @parallel
....: def foo(n):
....:         return str(factor(n))
....:
sage: foo(10)
'2 * 5'
sage: for x in foo([1..10]):
....:         print x[0][0][0]
....:
1
2
3
4
5
6
7
8
9
10


I expected to get the factorizations of 1 .. 10, not the numbers 1 .. 10. It seems like the output of foo() is getting evaluated somehow when it goes through the @parallel decorator. Is this a bug?