I noticed that cos(pi/6) gives 1/2*sqrt(3) as expected
but arccos(1/2*sqrt(3)) gives arccos(1/2*sqrt(3)).
Is it a missing feature or is there an option that you must call explicitely to obtain arccos(1/2*sqrt(3))=pi/6 ?

1 | initial version |

I noticed that cos(pi/6) gives 1/2*sqrt(3) as expected
but arccos(1/2*sqrt(3)) gives arccos(1/2*sqrt(3)).
Is it a missing feature or is there an option that you must call explicitely to obtain arccos(1/2*sqrt(3))=pi/6 ?

2 | No.2 Revision |

I noticed that cos(pi/6) gives 1/2*sqrt(3) as expected
but arccos(1/2*sqrt(3)) gives arccos(1/2*sqrt(3)).
Is it a missing feature or is there an option that you must call explicitely to obtain arccos(1/2*sqrt(3))=pi/6 ?

Thanks for your answer

3 | No.3 Revision |

I noticed that ~~cos(pi/6) ~~$\cos(\pi/6)$ gives ~~1/2~~*sqrt(3) **$(1/2)\sqrt{3}$ as expected but $\arccos((1/2)\sqrt{3})$ gives $\arccos((1/2)\sqrt{3})$.*

*Is it a missing feature or is there an option that you must call explicitely to obtain arccos(1/2*sqrt(3))=pi/6 $\arccos((1/2)\sqrt{3})=\pi/6$ ?

Thanks for your answer

4 | retagged |

I noticed that $\cos(\pi/6)$ gives $(1/2)\sqrt{3}$ as expected but $\arccos((1/2)\sqrt{3})$ gives $\arccos((1/2)\sqrt{3})$.

Is it a missing feature or is there an option that you must call explicitely to obtain $\arccos((1/2)\sqrt{3})=\pi/6$ ?

Thanks for your answer

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