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asked 1 year ago

Cyrille gravatar image

Using a function without specifying it

I want to ask sagemath if

|xa|f(x)dx=0(ax)f(x)dx+0(ax)f(x)dx

which is obviously true without specifying f(x)^(a probability density). Is this possible in SageMath.

Using a function without specifying it

I want to ask sagemath if

$\int_{-\infty}^\infty |x - a| f(x) dx = \int_{-\infty}^0 (a -x) f(x) dx + \int_{0}^\infty (a -x) (x -a) f(x) dx$

which is obviously true without specifying f(x)^(a probability density). Is this possible in SageMath.

Using a function without specifying it

I want to ask sagemath if

$\int_{-\infty}^\infty |x - a| f(x) dx = \int_{-\infty}^0 \int_{-\infty}^a (a -x) f(x) dx + \int_{0}^\infty \int_{a}^\infty (x -a) f(x) dx$

which is obviously true without specifying f(x)^(a probability density). Is this possible in SageMath.

Using a function without specifying it

I want to ask sagemath if

|xa|f(x)dx=a(ax)f(x)dx+a(xa)f(x)dx

which is obviously true without specifying f(x)^(a f(x) (a probability density). Is this possible in SageMath.

Using a function without specifying it

I want to ask sagemath if

|xa|f(x)dx=a(ax)f(x)dx+a(xa)f(x)dx

which is obviously true without specifying f(x) (a probability density). Is this possible in SageMath.SageMath ?