# Revision history [back]

### Unbrackable blanck

In the following code I am obliged to insert / to inside my fonction to obtain the desired result.

nl=3 #nombre de contraintes
nc=4  #nombre de variables
ring=QQ
A=matrix(ring,nl,nc,[1.5,2,4,3,4,1,2,1,2,3,1,2])
b=vector(ring,[550,700,200])
c=vector(ring,[4,6,3,1])

### code ####
def simplex_tableau_sf(A, b, c,cond=1) :
# A matrice des contraintes
# b vecteur des contraintes
# c vecteur des paramètres de l'objectif
# 1 (défaut) tableau

I=identity_matrix(A.nrows())
L=block_matrix([[A,I]],subdivide=False)
L=L.augment(b)
n=A.nrows()
m=A.ncols()
z1=vector([0 for i in range(n+1)])
c=flatten(-c)
z1=flatten(z1)
zc=vector(c+z1)
L=matrix(L.rows()+[zc])
rows = list(L)
hr=['$x_{}$'.format(i) for i in range(0,nc+nl)]
#hc=hr[nl+1:]+list('z')
hr=list('')+list(hr)+list('b')
#hc=['','$\\epsilon_1$','$\\epsilon_2$','$\\epsilon_3$','z']
hc=list('xc2')+['$x_{}$'.format(i) for i in range(4,7)]
if cond == 1 :
return t
elif cond != 1 :
return L


So is there a blank which can be used as a string

### Unbrackable blanck

In the following code I am obliged to insert / to inside my fonction to obtain the desired result.

nl=3 #nombre de contraintes
nc=4  #nombre de variables
ring=QQ
A=matrix(ring,nl,nc,[1.5,2,4,3,4,1,2,1,2,3,1,2])
b=vector(ring,[550,700,200])
c=vector(ring,[4,6,3,1])

### code ####
def simplex_tableau_sf(A, b, c,cond=1) :
# A matrice des contraintes
# b vecteur des contraintes
# c vecteur des paramètres de l'objectif
# 1 (défaut) tableau

I=identity_matrix(A.nrows())
L=block_matrix([[A,I]],subdivide=False)
L=L.augment(b)
n=A.nrows()
m=A.ncols()
z1=vector([0 for i in range(n+1)])
c=flatten(-c)
z1=flatten(z1)
zc=vector(c+z1)
L=matrix(L.rows()+[zc])
rows = list(L)
hr=['$x_{}$'.format(i) for i in range(0,nc+nl)]
#hc=hr[nl+1:]+list('z')
hr=list('')+list(hr)+list('b')
#hc=['','$\\epsilon_1$','$\\epsilon_2$','$\\epsilon_3$','z']
hc=list('xc2')+['$x_{}$'.format(i) for i in range(4,7)]