One can obtain all posets of binary trees for a given n as follows in Sage: n=4 posets = [bt.to_poset() for bt in BinaryTrees(n)]

Is there a quick method to obtain the list of all such posets up to isomorphism?

1 | initial version |

One can obtain all posets of binary trees for a given n as follows in Sage: n=4 posets = [bt.to_poset() for bt in BinaryTrees(n)]

Is there a quick method to obtain the list of all such posets up to isomorphism?

One can obtain all posets of binary trees for a given n as follows in ~~Sage:
~~Sage:

```
n=4
posets = [bt.to_poset() for bt in
```~~BinaryTrees(n)]~~BinaryTrees(n)]

Is there a quick method to obtain the list of all such posets up to isomorphism?

One can obtain all posets of binary trees for a given n as follows in Sage:

```
n=4
posets = [bt.to_poset() for bt in BinaryTrees(n)]
```

Is there a quick method to obtain the list of all such posets up to isomorphism?

4 | retagged |

One can obtain all posets of binary trees for a given n as follows in Sage:

```
n=4
posets = [bt.to_poset() for bt in BinaryTrees(n)]
```

Is there a quick method to obtain the list of all such posets up to isomorphism?

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