So from the link given here- https://ask.sagemath.org/question/8366/editing-entries-of-matrix/
From the answer given, I see that to replace a row (say row 1) on a matrix by a list say List 1, I just do
[1,:]=vector(List1).
For example,
K=Matrix(QQ,6,8)
A priori, this is just the 0 matrix. Now writing,
K[1,:]=vector([1,1,1,1,1,1,1,1])
will replace my first row of my 6 x 8 matrix with the entries all 1's. However, what if I just want to replace say row 1 but the last 6 entries so I will have [0,0,1,1,1,1,1,1]. Of course, I can just type out K[1,:]=vector([0,0,1,1,1,1,1,1]) but this is not viable for larger matrices.
An example would be say my K=Matrix(QQ,40,80) and I have a list given by L1=[1,1,1,1]. Suppose I want to replace the row 1 with 40th-43rd entry being L1.
Method 1- Type out 76 zeros and do K[1,:]=vector(L1 with 76 zeros). This is not really ideal.
Method 2- Replace entry by entry. This is also not ideal if my L1 is say of length 20.
Is there a way to just say something like K[1,40-43]=vector([L1])?
