# Putting a vector into part of a row of a matrix

So from the link given here- https://ask.sagemath.org/question/836...

From the answer given, I see that to replace a row (say row 1) on a matrix by a list say List 1, I just do

```
K[1, :] = vector(List1)
```

For example,

```
K = Matrix(QQ, 6, 8)
```

A priori, this is just the 0 matrix. Now writing

```
K[1, :] = vector([1, 1, 1, 1, 1, 1, 1, 1])
```

will replace my first row of my 6 x 8 matrix with the entries all 1's.

However, what if I want to replace say row 1 but only the last 6 entries
so I will have `[0, 0, 1, 1, 1, 1, 1, 1]`

. Of course, I can just type out

```
K[1, :] = vector([0, 0, 1, 1, 1, 1, 1, 1])
```

but this is not viable for larger matrices.

An example would be say my `K = Matrix(QQ, 40, 80)`

and I have a list given by `L1 = [1, 1, 1, 1]`

.
Suppose I want to replace the row 1 with 40th-43rd entry being `L1`

.

Method 1- Type out 76 zeros and do `K[1, :] = vector(L1 with 76 zeros)`

. This is not really ideal.

Method 2- Replace entry by entry. This is also not ideal if my `L1`

is say of length 20.

Is there a way to just say something like `K[1, 40-43] = vector([L1])`

?