### How to solve numericaly with arbitrary precision

Hello,

I want to solve a numerical equation for which I can only access by a lambda function, the M matrix is to big for the determinant to be computed on the symbolic ring.

```
f = lambda om: RRR(M.subs({omega:om}).change_ring(RRR).det())
```

But , find-root solve in the built in float type of Python which is lacking the precision I need. Is there a way in sage to solve numericaly with arbitrary precision?

Thank you

~~Regards~~Regards
(edited with example more in line with what I am trying to achieve)

```
sage: x=var('x')
```~~ ~~sage: M= Matrix(SR,[[cos(x),cosh(x)],[sin(x),sinh(x)]])
sage: RRR = RealField(200)
~~
sage:y ~~sage: f = ~~find_root(x**5-RRR(1),-100,100)
0.9999999999999886
~~lambda om: M.subs({x:om}).change_ring(RRR).det()
sage: ~~type(y)
<class 'float'>
~~find_root(f,1,2)