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On occasion of my original thread/ticket

https://ask.sagemath.org/question/41324/typo-in-sage-documentation/

https://trac.sagemath.org/ticket/24879

I've now noticed that the documentation is wrong at the end saying

In general if d=2^a 5^b m where m is coprime to 10, then s=max(a,b) and t is the order of 10 modulo d.

It must instead be

In general if d=2^a 5^b m where m is coprime to 10, then s=max(a,b) and t is the order of 10 modulo m.

For example, consider d=6 (i.e. m=3), then 10 doesn't have an order modulo d since they aren't coprime (there is no k≥1 so that 10^k = 1 mod 6). But 10 and m are coprime with 10^1 = 1 mod 3.

If I'm correct, could someone please open a ticket? I'm too incompetent for that.

On occasion of my original thread/ticket

https://ask.sagemath.org/question/41324/typo-in-sage-documentation/

https://trac.sagemath.org/ticket/24879

I've now noticed that the documentation is wrong at the end saying

In general if d=2^a 5^b m where m is coprime to 10, then s=max(a,b) and t is the order of 10 modulo d.

It must instead be

In general if d=2^a 5^b m where m is coprime to 10, then s=max(a,b) and t is the order of 10 modulo m.

For example, consider d=6 (i.e. m=3), then 10 doesn't have an order modulo d since they aren't coprime (there is no k≥1 so that 10^k = 1 mod 6). But 10 and m are coprime with 10^1 = 1 mod 3. 3 which means t=1. And in fact, the period length of 1/6 is 1.

If I'm correct, could someone please open a ticket? I'm too incompetent for that.