Hello,
I'm trying to solve a system of equations in the treatment of an equilibrium system. I don't get any answers when I use the code below as is.

If I define K = 4.48e-13:

```
var('x,y,z')
K=4.48e-13
xi=0.75
yi=0
zi=0
eq1=K==y^2*z/x^2
eq2=xi+yi==x+y
eq3=2*xi+yi+2*zi==2*x+y+2*z
solns = solve([eq1,eq2,eq3],x,y,z,solution_dict=True)
[[s[x].n(30), s[y].n(30), s[z].n(30)] for s in solns]
```

I get:

[]

I do get numbers when I change the known value of "K" in the 2nd line to 4.48e-10 or bigger.

```
var('x,y,z')
K=4.48e-10
xi=0.75
yi=0
zi=0
eq1=K==y^2*z/x^2
eq2=xi+yi==x+y
eq3=2*xi+yi+2*zi==2*x+y+2*z
solns = solve([eq1,eq2,eq3],x,y,z,solution_dict=True)
[[s[x].n(30), s[y].n(30), s[z].n(30)] for s in solns]
```

[[0.75039762 - 0.00068968040*I,
-0.00039762382 + 0.00068968023*I,
-0.00019881201 + 0.00034484028*I],
[0.75039762 + 0.00068968040*I,
-0.00039762382 - 0.00068968023*I,
-0.00019881201 - 0.00034484028*I],
[0.74920475, 0.00079524857, 0.00039762445]]

I did not test past 1e-10. I tried increasing the number of bits to 100 for all 3 unknowns with no luck. Is there any way to solve the problem using SageMath using the smaller number? Thanks!

~~ ~~```
var('x,y,z')
K=4.48e-13
xi=0.75
yi=0
zi=0
eq1=K==y^2*z/x^2
eq2=xi+yi==x+y
eq3=2*xi+yi+2*zi==2*x+y+2*z
solns = solve([eq1,eq2,eq3],x,y,z,solution_dict=True)
[[s[x].n(30), s[y].n(30), s[z].n(30)] for s in solns]
```