### how accelerate this simple program

Hello everybody. Here is my question
We seek integers of which the decimal part of their square root begin by 2017.
Sample: sqrt(10858) = 104.**2017**27....
Here is my program:

```
for n in range (1, 10^5):
if int( N(sqrt(n)).frac() * 10000 ) == 2017:
cpt += 1
```

the problem is it takes too much time.
For the bound 10^5 it takes about 55 sec on my iMac, for 10^6 it takes 620 sec, for 10^7 it takes almost 6000 sec ...
The question is to obtain the result for the bound 10^10 !